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mel-nik [20]
3 years ago
12

Please help me if you give the right answer I will give brainlest thank you

Mathematics
1 answer:
zvonat [6]3 years ago
3 0
No
No
Yes
Yes
Hope this helps
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What are the square number factors of 56?​
balandron [24]

Answer:

2,4,7,8,14,and 28

7 0
2 years ago
X + 3x² – 28x <br><br> Can you guys help me solve this in ax^2+bx+c <br> Thank you thank you
Molodets [167]

Answer:

3x²+(-27x) +0

Step-by-step explanation:

The given expression is :

x + 3x² – 28x

We need to solve this in the form of ax²+bx+c.

we can write the given expression as :

3x²-28x+x = 3x²-27x

= 3x²+(-27x) +0

If we compare the given expression with the general expression, we find that,

a = 3, b = -27 and c = 0

Hence, the required equation is 3x²+(-27x) +0.

3 0
2 years ago
A circle has a radius r=3 and a center at (3,-5). what is the general form of the circle
Aleks [24]

Answer:

yes it would be so do that

Step-by-step explanation:

5 0
3 years ago
What is the law of sines
galina1969 [7]
Sine is also known as Opposite over hypotenuse. 
5 0
3 years ago
Read 2 more answers
Three stamps can be attached to each other in various ways.how many ways might three stamps be attached?
ivanzaharov [21]
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula. 
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C. 
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space. 
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.


8 0
3 years ago
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