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Korvikt [17]
3 years ago
11

Factorized the expression 8+16

Mathematics
2 answers:
navik [9.2K]3 years ago
7 0
Factors of 18 are 1, 2, 3, 6, 9, 18. Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36. Factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.
erma4kov [3.2K]3 years ago
4 0
If you factorize 8+16 you get 8(1+2)
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LA Fitness charges a registration fee of $75 plus $35.75 per month for members. Gold's Gym charges a registration fee of $164 pl
kkurt [141]

Answer:

After 5 months

Step-by-step explanation:

Step one:

given data

LA Fitness charges a registration fee of $75 plus $35.75 per month for members

let the number of months be x

and the total charges be y

total is

y= 75+35.75x----------1

Gold's Gym charges a registration fee of $164 plus $17.95 for members

let the number of months be x

and the total charges be y

total is

y= 164+17.95x----------2

Step two:

equate 1 and 2

75+35.75x= 164+17.95x

solve for x

35.75x-17.95x=164-75

17.8x=89

divide both sides by 17.8

x=89/17.8

x=5 months

3 0
3 years ago
What is the y and x intercepts .
hichkok12 [17]

Answer:

y-intercept: (0, -5)

x-intercepts: (-5, 0) , (1, 0)

4 0
2 years ago
How many real solutions does this system of equations have? x^2 + y^2 = 36
Vinvika [58]

Answer:

C:  there are two real solutions

Step-by-step explanation:

x^2 + y^2 = 36 is the equation of a circle centered at the origin and with radius √36, or 6.  Even a rough sketch of this circle would enable you to visualize what is happening here.  

3x – y + 1 = 0 may be solved for y:  y = 3x + 1.  The y-intercept of this straight line is (0, 1).  Plot this point inside the circle of radius 6 mentioned above and then draw a straight line with slope m = 3 through it.  This line will intersect the circle in two places; they represent real solutions.

Alternatively, substitute 3x + 1 for y in x^2 + y^2 = 36:

x^2 + (3x + 1)^2 = 36, or

x^2 + 9x^2 + 6x + 1 = 36, or

10 x^2 + 6x + 1 - 36 = 0, or

10 x^2 + 6x - 35 = 0.  This is a quadratic equation.  We'll use the quadratic formula to find solutions which represent the intersections of this line with this circle:

The coefficients are a = 10, b = 6 and c = -35.  Thus, the discriminant is

b^2 - 4ac, or 6^2 - 4(10)(-35), or 1436.  

Because the discriminant is positive, we can safely conclude that there are two real solutions, that is, two different, real x-values, each representing the x-coordinate of a point of intersection of the circle and the line.

The correct answer to this prolem is C:  there are two real solutions.

4 0
3 years ago
Someone help me with my homework
Nutka1998 [239]

Answer:


Step-by-step explanation:

the second one is correct. the first one is wrong because shape C also has those angles. the third one is wrong because shape C also has no perpendicular sides. the fourth one is wrong because shape C also has 2 pairs of angles with the same measure.

5 0
3 years ago
Read 2 more answers
I NEED UR HELPFNGKFNKFJFF
alisha [4.7K]

For Q3, you can subsitute x = 2 and y = 5 into the systems

-5(2) + 5 = -5

so it's a solution for the first system

-4(2)+2(5) = 2

it's also a solution for the second system

8 0
2 years ago
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