Find the mean of the following data: 0, 5, 30, 25, 16, 18, 19, 26, 0, 20, 28
antiseptic1488 [7]
Answer:
17
Step-by-step explanation:
In order to find a mean in a data set you need to be able to add all numbers provided than divided them by the numbers given. which in this case
- 0+5+30+25+16+18+19+26+0+20+28= 187
- There are 11 number given so we take:
187/11
187/11= 17
Have a nice day!
Answer:
39%
Step-by-step explanation:
Let's find the answer by using the following formula:
selling price=(paid price)+((paid price)*(percent markup)) which can be written as:
percent markup=((selling price)-(paid price))/(paid price)
percent markup=(27.80-20)/20
percent markup=0.39=39%
In conclusion, the percent markup is 39%.
Answer:
25.9 m
Step-by-step explanation:
Add them all together.
Answer:
Step-by-step explanation:
rate = 3.5% per month
A) Six days later the bank calculated the daily interest.
so, time = 6 days
= 6 / 30 = 1/5 month
simple interest 

=35%
B) For $5000, t = 1 month
For $2000, t = 20 / 30 = 2/3 month
For $8000, t = 16/30 months
Simple interest for $5000

$175
Simple interest for $2000

=$46.67
Simple interest for $8000

=$149.33
Total amount in account at the end of 30 days is
= $5000 + $175 + $2000 + $46.67 + $8000 + $149.33
= $15371
Y=mx+b
m=slope
given
y=4x+5
m=4=slope
2.
for the points (x1,y1) and (x2,y2), the slope of the line passing trhough those points is (y2-y1)/(x2-x1)
given
(1,6) and (3,10)
slope=(10-6)/(3-1)=4/2=2
function 1 slope is 4
function 2 slope is 2
4>2
the first one has greater rate of change