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Ann [662]
3 years ago
9

16 pizzas is what percent of 32 pizzas

Mathematics
2 answers:
weeeeeb [17]3 years ago
7 0
16 pizzas is 50% of 32 pizzas because 16/32= 0.5= 50%
Ludmilka [50]3 years ago
5 0
Make 16% a decimal:16%=\frac{16}{100}=0.16 Now, multiply:0.16*32=5.12
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A tour director collected AED 258 for 13 tour packages. Tour packages A cost AED 18 and tour package B costs AED 22. How many of
yanalaym [24]

Answer:

6 packages B

7 packages A

Step-by-step explanation:

let the number of packages A be a and the number of packages B be b

Total number of packages is 13;

Thus;

a + b = 13 •••••(i)

Total package a cost is 18(a) = 18a

Total package b cost is 22(b) = 22b

Total of both is 258

18a + 22b = 258 •••••••(ii)

From i, a = 13-b

Put this in equation ii

18(13-b) + 22b = 258

234-18b + 22b = 258

4b = 258-234

4b = 24

b = 24/4 = 6

since;

a + b = 13

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a = 7

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3 years ago
Given that the slope of a line is 1/3, what is the slope of a line that is pependicular to it ?
lys-0071 [83]
The slopes of two perpendicular lines are negative reciprocals of each other. The slope of the line perpendicular to the one in this question is -3.
6 0
4 years ago
B. lam greater than 310. My number
KonstantinChe [14]

Answer:

four hundred and forty two

3 0
3 years ago
Activity
Sergio039 [100]

Answer:

A:

Dylan’s weight is d.

Twice Dylan’s weight is 2d.

Three pounds more than twice Dylan’s weight is 2d + 3.

So, the expression for Alan’s weight in terms of Dylan’s weight is 2d + 3.

B:

Dylan’s weight is d.

Three times Dylan’s weight is 3d.

Twelve less than three times Dylan’s weight is 3d − 12.

So, the expression for Bruce’s weight in terms of Dylan’s weight is 3d − 12.

C:

Cecil’s weight is the sum of Alan's weight and Bruce's weight.

Alan’s weight in terms of Dylan's weight is 2d + 3.

Bruce’s weight in terms of Dylan's weight is 3d − 12.

So, the expression for Cecil’s weight in terms of Dylan’s weight is (2d + 3) + (3d − 12).

D:

Cecil's weight is (2d + 3) + (3d − 12).

Find Cecil's weight by substituting Dylan’s weight (d = 45) into the expression above:

(2 × 45 + 3) + (3 × 45 − 12)

=  (90 + 3) + (135 − 12)

=  93 + 123

=  216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

E:

Yes, the expression can be simplified by using the Associative and Commutative Properties of addition and by combining the like terms in the expression.

F:

(2d + 3) + (3d − 12)

First remove the parentheses:

2d + 3 + 3d − 12.

Then group the like terms:

2d + 3d + 3 − 12.

Finally, add and subtract the like terms:

5d − 9.

The expression (2d + 3) + (3d − 12) simplifies to 5d − 9.

G:

Cecil’s weight in terms of Dylan’s weight is 5d – 9.

Find Cecil’s weight by substituting Dylan’s weight (d = 45) into the expression above:

(5 × 45) − 9

= 225 − 9

= 216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

H:

Yes, the answers are the same. The expression from part D is equivalent to the expression from part G.

I:

Bruce's weight in terms of Dylan’s weight is 3d − 12.

Alan's weight in terms of Dylan’s weight is 2d + 3.

So, the expression (3d − 12) − (2d + 3) represents how much more Bruce weighs than Alan.

J:

The expression is (3d − 12) − (2d + 3).

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

(3 × 45 − 12) − (2 × 45 + 3)

= (135 − 12) − (90 + 3)

= (123) − (93)

= 30.

Bruce weighs 30 pounds more than Alan weighs.

K:

The expression (3d − 12) − (2d + 3) simplifies to d − 15.

L:

The expression is d − 15.

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

45 − 15 = 30.

Bruce weighs 30 pounds more than Alan. This is the same answer as in part J.

Do not copy, it's the exact answer from edmuentum

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3 years ago
True or false. Potential rivals may be more likely to collude if they view themselves as playing a repeated game rather than a o
saveliy_v [14]

Answer: True

Step-by-step explanation:

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3 years ago
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