Its the third pair of inequalities
b 26 < n < 30
so n = 28
the 3 numbers are 28, 30 and 32
5x + 4y = 32 ⇒ 45x + 36y = 288
9x - 1y = 33 ⇒ <u>45x - 5y = 165</u>
<u>41y</u> = <u>123</u>
41 41
y = 3
5x + 4(3) = 32
5x + 12 = 32
<u> - 12 - 12</u>
<u>5x</u> = <u>20</u>
5 5
x = 4
(x, y) = (4, 3)
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
Zigmanuir [339]
The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.
49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52
For the median you want o line all of your number up from least to greatest and then find the middle number.
49,49,49,52,54,55,55
Your median is 52
The mode is the number that is listed most often
49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times
So, your mode is 49
Oh just complete it okay bae u got it
