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4 years ago

Triangle DEF has vertices on D(2,1) and E (7,1) and has an area of 15 square units. Plot a possible point F on the grid

1 answer:

7 0

The distance between D and E is 5 units and the area of a triangle is:

A=bh/2 if we let DE be the base and A=15 we have

15=5h/2

5h=30

h=6 (there are actually infinitely many solutions to create this height of 6 units high away from the base)

The simplest four are the right triangles formed when F is either:

(2,7), (2,-5), (7,7), and (7,-5)

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Evaluate for x= 7. (x + 1)(x + 2) x + 1 A) 5 B) 7 C) 8 D) 9

madam [21]

Answer:

A) 5

Step-by-step explanation:

(7 + 1)( 7+ 2) 7 + 1

6 0

3 years ago

Read 2 more answers

A major credit card company has determined that customers charge between $100 and $1100 per month. If the monthly amount charged

Alexxx [7]

Answer:

a) $E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600$

b) First we need to calculate the variance given by this formula:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33$

And the deviation would be:

$Sd(X) = \sqrt{83333.33}= 288.675$

c) $P(600 < X< 889) = P(X$

And using the cdf we got:

$P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289$

d) $P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578$

Step-by-step explanation:

For this case we define the random variable X who represent the customers charge, and the distribution for X on this case is:

$X \sim Unif (a= 100, b=1100)$

Part a

For this case the average is given by the expected value and we can use the following formula:

$E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600$

Part b

First we need to calculate the variance given by this formula:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33$

And the deviation would be:

$Sd(X) = \sqrt{83333.33}= 288.675$

Part c

For this case we want to find the percent between 600 and 889, so we can use the cumulative distribution function given by:

$F(x) = \frac{X -100}{1100-100}= \frac{x-100}{1000}, 100 \leq X \leq 1100$

And we can find this probability:

$P(600 < X< 889) = P(X$

And using the cdf we got:

$P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289$

Part d

$P(311 < X< 889) = P(X$

And using the cdf we got:

$P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578$

6 0

3 years ago

Sari is factoring the polynomial 2x2 5x 3. if one factor is (x 1), what is the other factor? 2x−3 2x 3 3x−2 3x 2

asambeis [7]

The other factor of the polynomial which Sari is factoring and found that the one factor of this equation is (x+1) is (2x+3).

<h3>What is a factor of polynomial?</h3>

The factor of a polynomial is the terms in linear form, which are, when multiplied together, give the original polynomial equation as a result.

The polynomial which Sari is factoring is,

$2x^2 +5x+ 3$