cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
Answer:
2
Step-by-step explanation:
it is talkin about 2
8 + 2 = 10
10 - 2 = 8
Answer:
4. -135
5. -420
Step-by-step explanation:
Hope this helps <33
Answer:
Look down
Step-by-step explanation:
9. x = 1 or 2 or x < 3
10. x ≤ 6
11. x < 4
12. x ≥ -6
13. x > 15
14. x ≤ -30
15. x < -48
16. x < 1
