First, find out x
x+15+2x+15=180
3x+30=180
3x=150
x=50
so the two angels are x+15=65(let's name is ∠5 for convenience), and ∠6= 2x+15=115
notice the two inner lines are marked as congruent, so
∠4=∠5=65
∠1=180-∠4-∠5=180-65-65=50
Name the right bottom angle ∠7, ∠3=∠7 and ∠3+∠7=the exterior angle 100 degree, therefore, ∠3=50
∠2+∠3=∠4, therefore, ∠2=∠4-∠3=65-50=15
∠1=50, ∠2=15, ∠3=50, ∠4=65
1) 30
2) 800
3) 500
4) 4,000
5) 9
6) 600
7) 7,000
8) 200,000
9) 2,000 * 10 = 20,000. 20,000 * 10 = 200,000.
All internal angles in a quadrilateral add to 360
so
x+110+110+70=360
x+290=360
minus 290 both sides
x=70 degrees
X intercept of line a is (-6,0)
x intercept of line b is (1,0)