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3 years ago

At the register Annie notices her grocery bill was marked with $14 for the 7 pounds of meat she purchased. What is another way

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

7 0

Answer:I think 2 Because if you have 7 and You add another its 14 so 2

Step-by-step explanation:Also can you make be braniest poss if not its ok :)

melamori03 [73]3 years ago

5 0

Answer:

2:1

Step-by-step explanation:

$2 for 1 pound of meat purchased

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Help please. I'm stuck

jok3333 [9.3K]

Answer:

The numbers are 65, 67, and 69

Step-by-step explanation:

Hi there!

We need to find 3 consecutive odd integers.

Consecutive numbers are numbers that follow each other (ex. 1, 2, 3, 4)

We're given that 5 times the first number + 4 times the second + 3 times the third = 800

Let's make the first number x

Since the second number is consecutive to the first and odd, it will be x+2 (Why? Well, let's say x is 5. In that case, x+1=6, which is even. However, x+2=7)

Therefore, the third number is x+4 (once again, if x is 5, x+3=8, but x+4=9)

5 times the first number is 5x

4 times the second is 4(x+2)

3 times the third is 3(x+4)

And of course, that equals 800

As an equation, it'll be:

5x+4(x+2)+3(x+4)=800

open the parenthesis

5x+4x+8+3x+12=800

combine like terms

12x+20=800

Subtract 20 from both sides

12x=780

Divide by 12 on both sides

x=65

The first number is x, so the first number is 65

The second number is x+2, or 65+2=67

The third number is x+4, or 65+4=69

Hope this helps!

8 0

3 years ago

I have no idea what im doing, can someone please help me? ASAP!!!! Use the pythagorean theorem to find the missing slide.

Solnce55 [7]

Answer:

1. b=√56

Step-by-step explanation:

1. Pythagorean therom states a²+b²=c² and in number 1 we are given the c or the hypotenuse so plugging in the values we know 13²+b²=15²

which equals 169+b²=225 subtract 169 from both sides and we get b²=56

square root both sides and we get b=√56

7 0

3 years ago

Mike collects trading cards. His favorites are baseball and football cards. For every 3 basebali cards he owns, Mike has 5 footb

Alecsey [184]

Answer:

56 cards

Step-by-step explanation:

If 5 baseball cards multiplied by 8 is 40, then you multiply the 7 football cards by 8 as well.

7x8=56

4 0

3 years ago

Read 2 more answers

Prove that (I ,+) is an abelian group where I = Set of integers

scoundrel [369]

Step-by-step explanation:

First we recall the relevant definitions and properties:

An even integer is an integer that is a multiple of 2, that is, an integer that can be written as 2k2k where kk is also an integer.

An abelian group is a set with an operation that is closed in that set, is associative, has an identity element, has inverses, and is commutative.

Addition is already associative and commutative over the set of all integers, and has an identity 00 and an inverse −n−n for each integer nn.

Oh, and multiplication of integers distributes over addition (this is important because we’re dealing with multiples of 2 but also with addition. The distributive property is how multiplication relates to addition).

This means we have to show a few things:

Addition is closed over the even integers. This holds due to the distributive property: if you have even integers 2k2k and 2m2m, then 2k+2m=2(k+m)2k+2m=2(k+m) is also an even integer. The odd integers fail this property: for example, 11 is odd but 1+1=21+1=2, which is not odd.

Addition is associative over the even integers. This holds because addition is already associative over the set of all integers: 2k+(2m+2j)=(2k+2m)+2j2k+(2m+2j)=(2k+2m)+2j. The odd integers do satisfy associativity, since they’re also a subset of the integers.

Addition has an identity element over the even integers. Since we already know that 00 is an identity for the set of all integers and 00 is even, this shows that we have an identity for the even integers: 2k+0=2k2k+0=2k. This doesn’t hold for the set of odd integers, because if nn and kk are odd integers and n+k=nn+k=n then k=0k=0, a contradiction since 00 is not odd.

Addition has inverses over the even integers. We already know that integers have inverses, and if 2k2k is an even integer then −k−k is the inverse of kk, so that 2k+2(−k)=2(k+(−k))=2(0)=02k+2(−k)=2(k+(−k))=2(0)=0. This means the even integer 2(−k)2(−k) is the inverse of 2k2k. The odd numbers do satisfy this property, since they’re also a subset of the integers.

Addition is commutative over the even integers. This holds because addition is already commutative over the set of all integers: 2k

6 0

3 years ago

Round 5.275 to the nearest hundredth

Angelina_Jolie [31]

5.28....What you do is find the hundredth place then locate the number to the right of it. If the number is greater than 4, then you round the hundredth place up a number and if it is less than or equal to 4 then leave the hundredth place alone. but in this case we round it up because 5 is greater than 4 so change 7 to eight.

6 0

3 years ago