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Irina18 [472]
3 years ago
13

45+(-38) ????????????????

Mathematics
2 answers:
mixer [17]3 years ago
6 0

Answer:

by me investigation i go to the naza i was with a high gpa in my high school by all the students that work really hard in this answer the anwer would be 7

Digiron [165]3 years ago
5 0

Answer:

65

Step-by-step explanation:

put the equation again plz

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The width of a math textbook is 0.75 inches. How many math textbooks can be placed standing up on a shelf that is 18 inches wide
larisa [96]
Since the width of each math textbook is 0.75 you have to find a number that multiplied by 0.75 will be equal 18

so, 0.75 x 24 = 18 

18 books can be placed in the shelf
5 0
3 years ago
Read 2 more answers
During a football game, the team lost 6 yards and then another 3 yards. How many yards behind the line of scrimmage are they?
Vika [28.1K]

Answer:

They are 9 yards behind

Step-by-step explanation:

Lost 6 yards: -6

Lost another 3 yards: -3

Add them together:

-6 + -3 = -9

They are 9 yards behind

6 0
4 years ago
The time T required to repair a machine is an exponentially distributed random variable with mean 10 hours.
Firdavs [7]

It can be expected about 36.79% of chance that repair time exceeds

The probability that a repair time exceeds  15 hours is 0.3679

What is the exponential distribution?

It explains about the time between events or the distance between two random events is termed the exponential distribution. Here, the occurrence of the events is continuous and also independent. Moreover, the average rate is constant.

The cumulative distribution function of T is obtained below:

From the information given, let the random variable T be the required time to repair a machine follows exponential distribution with parameter λ
with mean. 1/2 hours

That is,  E(x) =  1/2 hours.
The parameter of the random variable T is,
E(x) =  1/λ
λ = 1/E(x)
= 1/(1/2)
= 2

The probability density function of T is,
f(t) = \left \{ {{2e^{-2t} \ \ \ t > 0}  \  \atop {0} \ \ \ elsewhere} \ \right.
The cumulative density function of T is,
FT(t) = P(T <= t)

= 1 - e^{- \lambda t}

= 1 - e^{- 2t}
The CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise
to obtain the probability that a repair time exceeds

1/2 hours.
(a) The probability that a repair time exceeds 1/2 hours.
From the given information, the CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise

The required probability is,
P(T <= 1/2)  = 1 - P(T <= 1/2)
        = 1 - [  = 1 - e^{- 2(1/2)} ]
       = e^{-1}
= 0.3679

om total probability. It can be expected about 36.79% of chance that repair time exceeds

P(X => x)  = 1 - P(X < x)
to obtain the probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.

(b), The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained below:
From the given information, the CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise
The required probability is,
P = P(T => 12.5∩T>12) / P(T>12)
= e^{- 25 + 24}

= e^{- 1}
= 0.3679
The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained by dividing the
P = P(T => 12.5∩T>12) / P(T>12)
with
P(T>12).

It can be expected about 36.79% of chance that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.

Hence, It can be expected about 36.79% of chance that repair time exceeds,

The probability that a repair time exceeds  15 hours is 0.3679

To learn more about the product of the fraction visit,
brainly.com/question/22692312
#SPJ4

7 0
1 year ago
Yo yo Help a girl out LOL due today please help just need the answer &lt;3
Snezhnost [94]

Answer: The answer is 19 hours

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help this is really confusing !!
elena-14-01-66 [18.8K]
X - (1/5x + 1/2x + 1/4x)
= x - 19/20x
= 1/20x
= 0.05x (Written in decimal)

No, Josh is wrong. it should be 0.05x and not 0.5x
6 0
4 years ago
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