Question

John wants to invite around 78000 college students to a tournament. Which of the following sets of college student populations has a sum closest to 78000.

Answer 1

Answer: A  18 + 33 + 27 ~ 50 + 27 ~ 77  the closer  

B  15+ 47 + 27 ~ 60 + 27 ~87  

C  22 + 39 +32 ~ 62 + 32 ~ 94  

D

Answer 2

Set A has a college student population with the sum closest to 78,000.

Step-by-step explanation:

Step 1:

First, we need to determine the sums of college student populations.

Set 1; $18,432+32,761+27,390 = 78,583.$

Set 2;  $15,791+47,318+27,522 = 90,631,$

Set 3; $22,109+38,569+32,780 = 93,458,$

Set 4; $27,420 +47,338+22,183 = 96,941.$

Now we determine the difference in populations between the given sets and 78,000.

Set 1; $78,583 - 78,000 = 583,$

Set 2; $90,631-78,000 = 12,631,$

Set 3; $93,458-78,000 = 15,458,$

Set 4; $96,941-78,000=18,941.$

Set 1 has the minimum difference of all the sets, so it is the answer.