Answer:
92
Step-by-step explanation:
Lab Scores are 84, 81, and 93
Test Scores are 89 and 94
Each lab counts once and each test counts as two labs. At the end of the semester there is a final lab that counts as three regular labs.
Total Number of Labs= (3X1)+(2X2)+(1X3) =3+4+3 =10
To recieve an A(90), the average of her scores must be 90.
Let her final lab score =b
Refer to the attached diagram
Total Score=624+3b
For her average =90
Cross multiplying
624+3b =90 X 10
624+3b =900
3b =900-624
3b =276
Dividing both sides by 3
b= 92
She must score 92 in her final lab to receive an A.
Answer:
Step-by-step explanation:
From the question we are told that
Architect Measures 2.5 feet (using the Brussels measurement)
Generally in Brussels 
Therefore
Generally in Aalst 
Therefore Mathematically converting to feet in Aalst measurement we get
Answer:
2 solutions
Step-by-step explanation:
I like to use a graphing calculator to find solutions for equations like these. The two solutions are ...
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To solve this algebraically, it is convenient to subtract 2x-7 from both sides of the equation:
3x(x -4) +5 -x -(2x -7) = 0
3x^2 -12x +5 -x -2x +7 = 0 . . . . . eliminate parentheses
3x^2 -15x +12 = 0 . . . . . . . . . . . . collect terms
3(x -1)(x -4) = 0 . . . . . . . . . . . . . . . factor
The values of x that make these factors zero are x=1 and x=4. These are the solutions to the equation. There are two solutions.
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<em>Alternate method</em>
Once you get to the quadratic form, you can find the number of solutions without actually finding the solutions. The discriminant is ...
d = b^2 -4ac . . . . where a, b, c are the coefficients in the form ax^2+bx+c
d = (-15)^2 -4(3)(12) = 225 -144 = 81
This positive value means the equation has 2 real solutions.
