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3 years ago

In the figure, the perimeter of hexagon ABCDEF is approximately

Mathematics

2 answers:

Nikitich [7]3 years ago

7 0

First solve the length of side BC, CD, EF and FA Since BC = CD = sqrt( 10^2 + 10^2) BC = CD = 14.1421
FA = EF = sqrt(10^2 + 20^2) = 23.3607
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607 = 93

The area is made up be triangle FAE, rectangle ABDE and triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>

Veronika [31]3 years ago

7 0

Answer:

500

Step-by-step explanation:

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lina2011 [118]

Answer:

18 feet

Step-by-step explanation:

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2 years ago

Please help with answers A and B :)

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A. Terms
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3 years ago

The cost T, in dollars, of tuition and fees at Addison Technical College is $125 per credit plus an $85 registration fee. How ma

Sladkaya [172]

Answer:

Step-by-step explanation:

1710/125 = 13.68

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3 years ago

Tristan is working on dilating rectangles. Rectangle ABCD is dilated by a factor of 3. The resulting rectangle WXYZ has an area

zloy xaker [14]

Answer:

Tristan is correct, because he needs to find the possible dimensions for rectangle WXYZ and then divide each dimension by 3.

Step-by-step explanation:

The rectangle ABCD is dilated by a factor of 3 to get the rectangle WXYZ whose area is found to be 72 cm².

Let the dimensions of the dilated rectangle WXYZ are a cm by b cm.

So, ab = 72 ........... (1)

Now, the dimensions of the original rectangle are 3 times lesser than the dimensions of rectangle WXYZ.

So, the area of rectangle ABCD will be $(\frac{a}{3} \times \frac{b}{3}) = \frac{ab}{9} = \frac{72}{9} = 8$ cm² {from equation (1)}

Therefore, Tristan is correct, because he needs to find the possible dimensions for rectangle WXYZ and then divide each dimension by 3. (Answer)

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3 years ago

1. The sign outside Mrs. Washington’s catering company is in the shape of a trapezoid, as shown below.

inessss [21]

let's notice the tickmarks on the left and right sides, meaning those two sides are twins, and therefore equal, so the perimeter is simply 2.5+2.5+3.5+2.5 = 11 ft.

the trapezoid has an altitude/height of 2 ft, thus

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=2.5\\ b=3.5\\ h=2 \end{cases}\implies A=\cfrac{2(2.5+3.5)}{2}\implies A=6$

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3 years ago