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masya89 [10]
3 years ago
11

What answer should be reported, with the correct number of significant figures, for the following calculation? (965.43 × 3.911)

+ 9413.4136 What answer should be reported, with the correct number of significant figures, for the following calculation? (965.43 × 3.911) + 9413.4136 13189 1.3 × 104 1.319 × 104 13189.2 1.32 × 104
Mathematics
1 answer:
aleksklad [387]3 years ago
7 0

Answer:

The correct option is: 1.319 × 10⁴

Step-by-step explanation:

Significant figures or digits refers to the digits of a number that have meaning and also contribute to precision of the given number.

The scientific or standard form involves writing the significantly large or small numbers in decimal form. The standard form does not include any insignificant figures.

Therefore,

(965.43 × 3.911) + 9413.4136

= 3775.79673 + 9413.4136

= 13189.21033

Now, expressing in the standard form and rounding the answer to three digits after the decimal,

13189.21033 = 1.318921033 × 10⁴ = 1.319 × 10⁴ , has <u>four non-zero significant figures.</u>

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Elwin Osbourne, CIO at GFS, Inc., is studying employee use of GFS e-mail for non-business communications. A random sample of 200
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<em> The 90% confidence interval for the population proportion is</em>

<em>(0.10872, 0.19128)</em>

Step-by-step explanation:

<u><em>Explanation:</em></u>-

<u><em>Step(i)</em></u>:-

Given data A random sample of 200 e-mail messages was selected. Thirty of the messages were not business related

Given random sample size 'n' = 200

Given Thirty of the messages were not business related

 let 'x' = 30

<em>Probability of the messages were not business related or proportion</em>

<em></em>p = \frac{x}{n} = \frac{30}{200} = 0.15<em></em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>The 90% confidence interval for the population proportion is</em>

(p - Z_{0.10} \sqrt{\frac{p(1-p)}{n} } , p + Z_{0.10} \sqrt{\frac{p(1-p)}{n} } )

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The critical value   Z₀.₁₀ = 1.645

<em>The 90% confidence interval for the population proportion is</em>

(  0.15-1.645 \sqrt{\frac{0.15(1-0.15)}{200} } , 0.15 +1.645 \sqrt{\frac{0.15(1-0.15)}{200} } )

on calculation, we get

(0.15 - 0.04128 , (0.15 + 0.04128)

(0.10872, 0.19128)

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<em> The 90% confidence interval for the population proportion is</em>

<em>(0.10872, 0.19128)</em>

<em></em>

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