How many 3/4 cup servings are there in 8 cups of berries?

Given the following information, describe if one of the brands is a better buy

Anon25 [30]

Sorry but What information?

4 0

2 years ago

The mean for this data is 95 103,99,90,86,105,96

prisoha [69]

96.2857143 would be the answer because you add all the numbers together then divided by 7

5 0

3 years ago

Simplify 16 - 12 ÷ 4 +3 (6-2) show working plz

ira [324]

Answer:

20

Step-by-step explanation:

16-12/4+3(6-2) subtract 6 and 2

16-12/4+3+4 divide 12 and 4

16-3+3+4 subtract 16 and 3

13+3+4 add all 3 numbers

13+7

20

4 0

2 years ago

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

2 years ago

FUNNY MEMES THE FUNNIEST GETS BRAINLIEST!!!!!!!!!!!!!!!!

diamong [38]

Answer:

Does February March?.... NO, but APRIL MAY

Step-by-step explanation:

Does February March?.... NO, but APRIL MAY

\Does February March?.... NO, but APRIL MAY

Does February March?.... NO, but APRIL MAY

3 0

2 years ago

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