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anastassius [24]
3 years ago
15

Consider -q > 5. Use the addition and/or subtraction property of inequality to solve.

Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0

The correct answer would be -5 > q

In order to solve this using only addition and subtraction, what we need to do is change the side each term is on. This will allow us to get the variable to be a positive number.

-q > 5 ----> Subtract 5 from both sides

-5 - q > 0 -----> Add q to both sides

-5 > q

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To add fractions, find the LCD and then combine.

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Decimal form:

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Mixed number form:

4 1/2

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4 1/2

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2 years ago
A secret code is made up of three digits followed by
kari74 [83]
Most likely 10 because the initial amount is 5
5 0
3 years ago
How do I solve this????
Arlecino [84]
Let's say the numbers are "a" and "b"
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4 more than "that", will be "that" + 4
or
5a + 4

so.. whatever "a" is, "b" is 5a+4

now, their sum is 22, as opposed to "zz" hehe

so       \bf \begin{cases}&#10;a+b=22\\&#10;--------------\\&#10;\boxed{b}=5a+4\qquad thus\\&#10;--------------\\&#10;a+\boxed{5a+4}=22&#10;\end{cases}

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3 0
3 years ago
Find the point, M, that divides segment AB into a ratio of 2:3 if A is at (0.15) and B is at (20.0)
timama [110]

Answer:

M = (8,9)

Step-by-step explanation:

Notice that the points (0,15), and (20,0) form with the origin of coordinates (0,0),  a right angle triangle (please see attached image). This triangle has twon perpendicular sides of length 15 and 20 respectively. Therefore, we can find the length of the segment that joins points A (0,15) and B (20,0) by finding the length of the hypotenuse in a right angle triangle (with the Pythagorean Theorem):

AB=\sqrt{15^2+20^2} =\sqrt{625} =25

Now, to get a 2:3 proportion on Segment AB which is of length 25, we need to divide it in five equal parts (see the picture on the right of the attached image), and place point M at two of these divisions from point A (0,15) and along segment AB.

In order to find the appropriate location in (x,y) coordinates, we consider a smaller triangle (pictured in orange in the image) that is similar to the first larger triangle (pictured in blue). Notice that if the length of AB is 25,  each of its five equal divisions would be of length "5", and therefore two of them will render a length of "10" (which is the hypotenuse of this smaller right angle triangle.

Now, in order to find the sides of this smaller triangle (which can give us the clues on the horizontal and vertical coordinates of point M), we can use proportions.

To find the length "x" of the horizontal side , we do:

\frac{x}{10} =\frac{20}{25} \\x=\frac{10*20}{25} \\x=8

To find the length "y" of the vertical side , we do:

\frac{y}{10} =\frac{15}{25} \\y=\frac{10*15}{25} \\y=6

Then, the coordinate "x" of point M will be "8", while we can calculate the y position of point M subtracting "6" from 15 (the length of the vertical side in the original triangle). This gives us the coordinates (8,9) for point M as marked in orange in the picture.

7 0
3 years ago
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