The sign of "b" on the numerator should be negative. So we conclude that the correct option is false.
<h3>Is the equation in the image correct or incorrect?</h3>
For a quadratic equation of the form:
![y = a*x^2 + b*x + c](https://tex.z-dn.net/?f=y%20%3D%20a%2Ax%5E2%20%2B%20b%2Ax%20%2B%20c)
By using the Bhaskara's formula, the solutions of the equation:
![0 = a*x^2 + b*x + c](https://tex.z-dn.net/?f=0%20%3D%20a%2Ax%5E2%20%2B%20b%2Ax%20%2B%20c)
Are given by the formula:
![x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2%20-%204ac%7D%20%7D%7B2a%7D)
Notice that the sign of the first term on the numerator should be negative, while on the image it is positive.
So the equation shown in the image is incorrect.
If you want to learn more about quadratic equations:
brainly.com/question/1214333
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Answer:
c
Step-by-step explanation:
i know it c
Write an equation to show all elements:
Cost of 4 lots of b (beads) + cost of 4p (pendants) = $18.80
Put values in;
9.29 + 4p = 18.80
4p = 18.80 - 9.20
4p = 9.60
p = 2.40 cost of each pendant
When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12
So in order that the given equation has double roots, the possible values of b are ± 12.