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Damm [24]
3 years ago
15

Formula: A=bh/2 if b=50 and h=20, then A=? Can someone explain how to solve this?

Mathematics
1 answer:
ki77a [65]3 years ago
7 0
Substiture b for 50 and h for 20 so
(50)(20)
1000/2
A = 500
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The scale factor of two similar solids is 6:13 determine the ratio of their corresponding areas and the volume of the larger sol
maksim [4K]
1. If the scale factor is k=6:13, then the ratio of their corresponding area is k^{2}=6^{2} :13^{2} =36:169;
2. \frac{V_{small\ solid}}{V_{big\ solid}} =k^3= \frac{6^{3}}{13^{3}} = \frac{216}{2197}.
6 0
3 years ago
Please help with the questions in the image
Pavel [41]

Answer:   f(x) = (x - 3)²

<u>Step-by-step explanation:</u>

Use the vertex formula: y = a(x - h)² + k

and input the vertex (h, k) = (3, 0) and the given point (x, y) = (4, 2) to solve for a

2 = a(4 - 3)² + 0

2 = a(1)²

2 = a

Now, input (h, k) = (3, 0) and a = 1 into the vertex formula:

y = 1(x - 3)² + 0    →     y = (x - 3)²  

****************************************************************************

Answer:   g(x) = -(x + 1.25)² + 2.5625

<u>Step-by-step explanation:</u>

Use the vertex formula: y = a(x - h)² + k

and input the given points for (x, y) to create a system of equations, then solve for a, h, and k.

EQ1: 2 = a(-2 - h)² + k  

       2 = a(4 + 4h + h²) + k

       2 - 4a - 4ah - ah² = k


EQ2: 1 = a(0 - h)² + k

        1 = ah² + k

        1 - ah² = k


EQ3: -2.5 = a(1 - h)² + k

        -2.5 = a(1 - 2h + h²) + k

        -2.5 -a + 2h + ah² = k

<u>Substitute</u> - set EQ1 = EQ2 and EQ2 = EQ3 to eliminate k

EQ1 = EQ2:     2 - 4a - 4ah - ah² = 1 - ah²

                                 1 - 4a - 4ah = 0    

EQ2 = EQ3:     1 - ah² = -2.5 - a + 2ah - ah²

                                3.5 + a - 2ah = 0  

<u>Elimination:</u>  - now solve the system for "a"

 1 - 4a - 4ah = 0    →    1(1 - 4a - 4ah = 0)    →     1 - 4a - 4ah = 0

3.5 + a - 2ah = 0   →   -2(3.5 + a - 2ah = 0) →  <u> -7 - 2a + 4ah = 0 </u>

                                                                         -6 - 6a           = 0

                                                                              -6a            = 6

<h2>                                                     a     = -1</h2>

Next, replace "a" with -1 into either of the equations to solve for "h"

                                         1 - 4a - 4ah = 0

                                     1 - 4(-1) - 4(-1)h = 0

                                            1 + 4 + 4h = 0

                                                 5 + 4h = 0

                                                       4h = -5

<h2>                                     h = -1.25</h2>

Now, replace "a" with -1 and "h" with -1.25 into any of the original equations (EQ1, EQ2, or EQ3) to solve for k:

1 - ah² = k

1 - (-1)(-1.25)² = k

1 - (-1)(1.5625) = k

1 + 1.5625 = k

<h2> 2.5625 = k</h2>

Now, input (h, k) = (-1.25, 2.5625) and a = -1 into the vertex formula:

y = -1(x - (-1.25))² + 2.5625    →     y = -(x + 1.25)² + 2.5625

4 0
3 years ago
in 2009 , first baseman matt craig of jacksonville suns southern league double-A baseball team had 24 hits in 80 times at bat .
maw [93]
Divide 24 by 80: 24/80=.3 :)
6 0
3 years ago
A town is designing a rectangular park that will be 600 feet wide by 1000 feet long. On a scale drawing, the dimensions of the p
KonstantinChe [14]

Scale drawing takes scaled versions of original lengths. The actual length of the swing set area of the park is 25 ft long and 100 ft wide

<h3>How are scale drawings formed?</h3>

For a particular scale drawing, it is already specified that all the measurements' some constant scaled version will be taken. For example, let the scale be K feet to s inches.

Then it means

\rm 1\:  ft : \dfrac{s}{k}\:  in.

All feet measurements will then be multiplied by s/k to get the drawing's corresponding lengths.

For the given case, it is given that

Real dimension of a rectangular park : 600 ft by 1000 ft

In drawing, it was of 12 inches by 20 inches.

Let the scale that the drawing is using be k feet to s inches, then

\rm 1\:  ft : \dfrac{s}{k}\:  in.

Since it is given that 600 ft : 12 inches and 1000 ft : 20 inches, thus, we get:

\rm 1\:  ft : \dfrac{s}{k}\:  in.\\\\600 \: ft = \dfrac{600\times s}{k} \: in. =  12 \: in.\\\\\dfrac{600 \times s}{k} = 12\\\\\dfrac{s}{k} = \dfrac{12}{600} = 0.02

Thus, every feet is reduced 0.02 times in drawing.

Now,

it is given that in drawing, the rectangular area for swing sets is 0.5 inch to 2 inch.

Let its real length was L and real width was W. Then we have:
\rm L \times 0.02 = 0.5 \\\\L = \dfrac{0.5}{0.02} = 25 \:\\\\W \times 0.02 = 2 \\W = \dfrac{2}{0.02} = 100

Since these are only magnitudes, and unit was converted from feet to inches, so we have L = 25 feet and W = 100 feet

Thus,

The actual length of the swing set area of the park is 25 ft long and 100 ft wide

Learn more about scaling here:
brainly.com/question/8765466

6 0
2 years ago
What is the slope of the equation Y=5/4x-7/4?
maksim [4K]

Answer:

Step-by-step explanation:

Compare the equation with y = mx + b where m is slope and b is y intercept

y = (5/4)x - (7/4)

Slope = m = 5/4

4 0
2 years ago
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