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3 years ago

If you are trying to move an attached term across the equal sign (=), what operation would you use to move it?

Mathematics

1 answer:

n200080 [17]3 years ago

7 0

Answer: If we are trying to move an attached term across the equal sign (=), then we use inverse operation .

Step-by-step explanation:

If we are trying to move an attached term across the equal sign (=), then we use inverse operation .

The inverse operations are the opposite operations that reverses the operation of the another operation.

Addition and subtraction are inverse operations.

Multiplication and division are inverse operations.

We can perform the same inverse operation on each side of an equivalent equation without changing the equality.

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The hypothesis test of cost parameters indicates whether: a.the total cost is similar to that of the prior periods. b.the parame

maksim [4K]

Answer:

B. The Parameter are different from Zero

Step-by-step explanation:

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2 years ago

Adding fractions 1/6+2/3=

mars1129 [50]

Answer:

$\frac{5}{6}$

$\frac{1}{6} + \frac{2}{3}$ is equivalent to $\frac{1}{6} + \frac{4}{6}$ .

This is because $\frac{2}{3}=\frac{4}{6}$

The rule is, in order to add fractions, your denominators must be equivalent. In other words, you must have the same denominator for both fractions.

$\frac{1}{6} + \frac{4}{6} =\frac{5}{6}$

This is because 4 + 1 = 5.

Your answer is $\frac{5}{6}$ .

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

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3 years ago

Read 2 more answers

Which is an equation in point-slope form for the given point and slope point (8 -4) slope 5/6

Alina [70]

If you want to say thank you, click the "Thanks" button and select the answer "The Brainliest!" We appreciate it!

Step-by-step explanation:

Point slope form: (y−y1) = m (x−x1), where (x1,y1) is the point, and m is the slope.

(y- (-4)) = (5/6)*(x - 8)

(y + 4) = (5/6)*(x - 8)

If you want in standard form

(y + 4) = (5/6)*x - (5/6)*8

y = (5/6) x - (5/6)*8 - 4

y = (5/6)x - (16/6)

Answer:

(y + 4) = (5/6)*(x - 8)

4 0

2 years ago

More math help please!

Nata [24]

AS we know that:

$V=SA*h$

And we have the volume and we can calculate the SA,,,

So that, we can conclude:
$h= \frac{V}{SA} = \frac{323.5}{\pi (7)^2} =2.1015~~in$

Are you satisfied?

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2 years ago

Read 2 more answers

I. Tell whether each statement is TRUE or FALSE. Refer to the figure below. Write your answer on the space provided.

Vika [28.1K]

Answer:

1. TRUE

2. TRUE

3. TRUE

4. TRUE

5. FALSE

6. TRUE

Step-by-step explanation:

1. From the diagram, we have that m∠2 and m∠7 are alternate interior angles

If m∠2 = 70° and m∠7 = 70°, then we have;

m∠2 = 70° = m∠7

m∠2 = m∠7

Therefore, the alternate interior angles of the lines l₁, and l₂ are equal, and therefore, the lines l₁ and l₂ are parallel, l₁ ║ l₂

TRUE

2. If m∠3 = 90° and m∠7 = 90°, therefore, the angle formed by the intersection of l₃ and l₂ = 90°

Therefore l₃ ⊥ l₂

TRUE

3. m∠5 and m∠7 are corresponding angles

If m∠5 = 85° and m∠7 = 85°, then, m∠5 = m∠7

Therefore, the corresponding angles formed by the lines l₁ and l₂ are equal, therefore;

l₁ ║ l₂

TRUE

4. Whereby we have, m∠1 = m∠5, we get;

m∠1 + m∠5 = 180° by sum of angles on a straight line

∴ m∠1 + m∠5 = m∠1 + m∠1 = 2·m∠1 = 180°

m∠1 = 180°/2 = 90°

∴ m∠1 = 90° = m∠5, and l₃ ⊥ l₁

TRUE

5. m∠1 and m∠8 are alternate exterior angles

If m∠1 = 98° and m∠8 = 82°

∴ m∠1 ≠ m∠8 and l₁ ∦ l₈

FALSE

6. Given that l₁║ l₂, then the angle formed between l₁ and l₃ will be equal to th angle formed between l₂ and l₃

Therefore;

If l₁║ l₂, and l₃ ⊥ l₁, then l₃ ⊥ l₂

(If l₁║ l₂, and l₃ is perpendicular to l₁, then l₃ is also perpendicular to l₂)

TRUE

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2 years ago