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marishachu [46]
3 years ago
8

After 273 m3 of ethylene oxide is formed at 748 kPa and 525 K, the gas is cooled at constant volume to 293 K.The new pressure is

_____kPa
Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
5 0
P1/T1 = P2/T2 

<span>748 / 525 = P2/293 </span>

<span>P2 = 748/525 X 293 = 417.455 kPa </span>
Schach [20]3 years ago
5 0

Answer:

Therefore, the new pressure is 417.455 kPa

Step-by-step explanation:

As per general gas equation

\frac{P_{1}V_{1}}{T_{1} }=\frac{P_{2}V_{2}}{T_{2} }

If Volume of a gas is constant then equation is represented by

\frac{P_{1}}{T_{1} }=\frac{P_{2}}{T_{2} }

Here P_{1}=748kPa and T_{1}=525K

If T_{2}=293K then we have to calculate the value of P_{2}

Now we plug in the values in the equation

\frac{748}{525}=\frac{P_{2}}{293}

P_{2}=\frac{(748)(293)}{525}

P_{2}= 417.455 kPa

Therefore, the new pressure is 417.455 kPa

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