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quester [9]
3 years ago
14

Which trinomial is a perfect square trinomial? a2 – 18a + 36 a2 – 16a + 64 a2 – 8a + 64 a2 – 6a + 36

Mathematics
1 answer:
Komok [63]3 years ago
4 0

Answer:

a^2-16a+64

Step-by-step explanation:

we have the options

a^2-18a+36\\a^2-16a+64\\a^2-8a+64\\a^2-6a+36

the one that is a perfect equare tinomial is:

a^2-16a+64

because we can rewrite this as follows:

(a-8)^2  this is because we know that

x^2-2xy+y^2=(x-y)^2

thus

a^2-16a+64=(x-8)^2

and the other options cannot be represented as a perfect square trinomial, so the correct answer is:

a^2-16a+64

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Which is the correct solution to -6x < 18? answer
saveliy_v [14]

Answer:

x> -3

Step-by-step explanation:

All you need to do is isloate x as if it were an equation -

\frac{-6x}{-6} = \frac{18}{-6}\\x> -3

You filp the sign when you divide by a negative number.

Hope this helped :)

4 0
4 years ago
Read 2 more answers
How do you do this question?
Maksim231197 [3]

Answer:

π/10

Step-by-step explanation:

When we rotate the region about the y-axis, we get something that looks like a volcano, or a bundt cake.  Instead of slicing this into flat washers, we'll slice it in concentric rings, or "shells".

Each shell has a radius x, a thickness dx, and a height y.  The volume of an individual shell is:

dV = 2π r h t

dV = 2π x y dx

Since y = x² − x³:

dV = 2π x (x² − x³) dx

dV = 2π (x³ − x⁴) dx

The total volume is the sum of all the shells from x=0 to x=1.

V = ∫ dV

V = ∫₀¹ 2π (x³ − x⁴) dx

V = 2π (¼ x⁴ − ⅕ x⁵) |₀¹

V = 2π (¼ − ⅕)

V = π/10

5 0
3 years ago
Identify the greatest rommon factor:<br> 3x²y - 6xy2
Over [174]
The answer is : 3xy(x-2y)
6 0
3 years ago
Read 2 more answers
Let’s say a GWC coder is working on a project that includes 6 x (8 +7) lines of code. Rewrite this expression in words.
Sladkaya [172]
Six times (eight plus seven)
3 0
3 years ago
What is the solution to the system of equations?
Minchanka [31]

Answer:

  (1, –5)

Step-by-step explanation:

It is relatively easy to try the offered solutions to see what works.

<u>(1, -5)</u>

  3(1) +10(-5) = -47 . . . true

  5(1) -7(-5) = 40 . . . true

(1, -5) is the solution

_____

As a check, you can try some of the other choices:

<u>(1, 5)</u>

  3(1) +10(5) ≠ -47

<u>(-1, -5)</u>

  3(-1) +10(-5) ≠ -47

<u>(-1, 5)</u>

  3(-1) +10(5) ≠ -47

None of the other choices works in the first equation, so they're not the solution.

4 0
3 years ago
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