Answer:
72%
Step-by-step explanation:
QT has length 42-24 = 18.
ST has length 42-29 = 13.
The length ST is 13/18 ≈ 72.2% of the length of QT.
The sequence can be represented by
, where
is a whole number(
and
is an integer). By this, we should be able to plug in some whole number x and be able to get these values if they are in the sequence. To test this, let's set these numbers equal to
and confirm that there is a whole number x which equals the values selected.



When trying 160 with our equation, we find that x doesn't equal a whole number, thus our answer is C, or 160. To confirm our answer, we can test 170 and 210 and confirm that they both give us a value for x which is a whole number.


Answer:
44.99
Step-by-step explanation:
284.97(total cost) - 194.99(system cost) = 89.98(money spent on games) / 2(total games) = 44.99 = 44.99 spent per game.
(a)
since 13 is prime.
(b)
, and there are 81/3 = 27 multiples of 3 between 1 and 81, which leaves 81 - 27 = 54 numbers between 1 and 81 that are coprime to 81, so
.
(c)
; there are 50 multiples of 2, and 20 multiples of 5, between 1 and 100; 10 of these are counted twice (the multiples of 2*5=10), so a total of 50 + 20 - 10 = 60 distinct numbers not coprime to 100, leaving us with
.
(d)
; there are 51 multiples of 2, 34 multiples of 3, and 6 multiples of 17, between 1 and 102. Among these, we double-count 17 multiples of 2*3=6, 3 multiples of 2*17=34, and 2 multiples of 3*17=51; we also triple-count 1 number, 2*3*17=102. There are then 51 + 34 + 6 - (17 + 3 + 2) + 1 = 70 numbers between 1 and 102 that are not coprime to 102, and so
.
Answer:
7 people
Step-by-step explanation:
Start with $160. and subtract $12 for parking because you have to pay that no matter how many people you buy tickets for.
160-12=148
Now you can see how many tickets you can buy with $148 by dividing by the price of the ticket which is $20.50
148/20.5=7.21951219512
You can buy 7 tickets
if you do the math, there is $4.50 leftover