<u>Answer:</u>
- 40% of the total marbles are green.
<u>Step-by-step explanation:</u>
Percentage: Green marbles/Total marbles
- => 8/5 + 4 + 8 + 3
- => 8/20
<u>Percentage formula:</u>
<u />
- => 8/20 x 100
- => 8 x 5
- => 40
Hence, 40% of the total marbles are green.
Hoped this helped.

Answer:
7.855
Step-by-step explanation:
A=pi*r^2=3.142*5^2=3.142*25=7.855
Answer:
4th one
Step-by-step explanation:
must be ![\sqrt[6]{x^{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Bx%5E%7B5%7D%20%7D)
Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.