Michael makes 60% of his free-throw attempts. If Michael attempts two free-throws,
1 answer:
<h3>
Answer: 12/25</h3>
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Reason:
60% = 60/100 = 0.6 is the probability of making any given free-throw.
1 - 0.6 = 0.4 is the probability of missing any given free-throw.
We have these probabilities
- A = P(making 1st, missing 2nd) = 0.6*0.4 = 0.24
- B = P(missing 1st, making 2nd) = 0.4*0.6 = 0.24
The probability of making exactly one free throw is A+B = 0.24+0.24 = 0.48
Convert this to a fraction:
0.48 = 48/100 = (4*12)/(4*25) = 12/25
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