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noname [10]
3 years ago
14

Do you use the same principle when adding and subtracting as you would multiplying in fractions?

Mathematics
2 answers:
dimaraw [331]3 years ago
7 0
No that wouldn't work.
e.g 1/2 + 1/2 would become 2/4 (which is equivalent to 1/2) if you just added the numbers, which can't be right.

You need to find equivalent fractions so that each fraction has the same number on the bottom (denominator) and then add ( or take away) the top numbers.

1/2 + 1/2 has same number on bottom, so just add top numbers to get 2/2 =1

so 1/4 + 1/2 has diff nos on bottom, so change 1/2 to 2/4.
1/4 + 2/4 = 3/4

2/3 - 1/4 = 8/12 - 3/12 = 5/12

You may need to ask your teacher about equivalent fractions.
Shtirlitz [24]3 years ago
7 0
Your answer is no hope i helped good luck with your homework
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3/8 of a scholarship fund was 1500 find the full amount of the scholarship fund​
N76 [4]

Answer:

The full scholarship fund will be 4000

Step-by-step explanation:

When doing these types of problems I like to do this.

1500 ÷ 3 = 500 (We do this because you want to find out what 1/8 is)

Since 500 is 1/8 of the part, all you have to do is multiply 500 by 8

500 × 8 = 4000

7 0
3 years ago
Factor 4y^2 - 4y - 20
jekas [21]
Factor is boof triangles because 4y-20 is 420 of em
6 0
2 years ago
A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d
Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
3 years ago
What two formulas are necessary to find the area of a segment of a circle?
Andrew [12]

Answer:

Step-by-step explanation:

Area of a Segment in Radians A = (½) × r2 (θ – Sin θ)

Area of a Segment in Degrees A = (½) × r 2 × [(π/180) θ – sin θ]

3 0
2 years ago
Macs farm has a total of 18 horses and 27 cows. what is the ratio of horses to cows in simplest form?
Evgesh-ka [11]
The ratio is basically finding the quotient of two numbers. If you want to find the ratio of horses to cows, divide the number of horses to that of cows.

Ratio = 18/27

When expressing it to its simplest form, make sure it is reduced. 18 and 27 are both factors of 9. So,

Ratio = 9*2/9*3
Cancelling out 9, the ratio at its simplest form is: <em>2/3</em>
7 0
2 years ago
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