Answer:
m=17
Step-by-step explanation:
$15 minus $0.14(# minutes) = $12.62
15 - .14m = 12.62
.14m = 15 - 12.62
.14m = 2.38
m = 2.38/.14
m = 17 minutes
1 1/100
.01 is the same as saying "one hundredth"
This can be treated as a proportion problem.
Larger solid:
Surface area = 1,372 cm²
Volume = 1,801 cm³
Smaller solid:
Surface area = 1,008cm²
Volume = ?
1,372 / 1,801 = 1008 / x
1,372 * x = 1,801 * 1008
1,372x = 1,815,408
x = 1,815,408 / 1,372
x = 1,323.18
The volume of the smaller solid is 1,323.18 cm³
<em><u>Complete Question:</u></em>
A restaurant uses 4.375 pounds of cheese every 8 and 3/4 pizzas. At this rate how many pounds of cheese are used per pizza?
<em><u>Answer:</u></em>
0.5 pounds of cheese are used per pizza
<em><u>Solution:</u></em>
Given that,
A restaurant uses 4.375 pounds of cheese every 8 and 3/4 pizzas
Therefore,
![4.375\ pounds = 8\frac{3}{4}\ pizza \\\\4.375\ pounds = \frac{35}{4}\ pizza](https://tex.z-dn.net/?f=4.375%5C%20pounds%20%20%3D%208%5Cfrac%7B3%7D%7B4%7D%5C%20pizza%20%5C%5C%5C%5C4.375%5C%20pounds%20%20%3D%20%5Cfrac%7B35%7D%7B4%7D%5C%20pizza)
We have to find pounds used per pizza
Let "x" be the pounds used per pizza
Then,
![4.375\ pounds = \frac{35}{4}\ pizza \\\\x\ pounds = 1\ pizza](https://tex.z-dn.net/?f=4.375%5C%20pounds%20%20%3D%20%5Cfrac%7B35%7D%7B4%7D%5C%20pizza%20%5C%5C%5C%5Cx%5C%20pounds%20%3D%201%5C%20pizza)
By cross multiplying,
![4.375 \times 1 = x \times \frac{35}{4} \\\\x = 0.5](https://tex.z-dn.net/?f=4.375%20%5Ctimes%201%20%3D%20x%20%5Ctimes%20%5Cfrac%7B35%7D%7B4%7D%20%5C%5C%5C%5Cx%20%3D%200.5)
Thus, 0.5 pounds of cheese are used per pizza
Answer:
1). Corresponding angles
2). Vertical angles
Step-by-step explanation:
1). Lines 'k' and 'l' are the parallel lines and line 'm' is a transverse.
Since m∠ABC = 19°
Therefore, m∠ECF = 19° [Corresponding angles]
(By translating line 'l' from the points B to C, angle ABC overlaps angle ECF)
2). Since, ∠ECF and ∠BCD are the vertical angles they will be equal in measure.
Therefore, m∠ECF = m∠BCD = 19°