Answer:
The equation is in the form y=mx+b, where m=slope, b=y-intercept.
The y-intercept is 35: so the line goes through the y-axis at (0,35).
The slope is 25: so we need to count out the slope as rise over run, or 25 up and 1 to the right, starting from the y-intercept.
Solution :
Given initial velocity, v= 48 ft/s
Acceleration due to gravity, g = 
a). Therefore the maximum height he can jump on Mars is


= 96 ft
b). Time he can stay in the air before hitting the ground is


= 8 seconds
c). Considering upward motion as positive direction.
v = u + at
We find the time taken to reach the maximum height by taking v = 0.
v = u + at
0 = 16 + (12) t


We know that, 
Taking t =
, we get

feet
Thus he can't reach to 100 ft as it is shown in the movie.
d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.
Therefore final velocity is = -16 ft/s
365*24*60*60=31536000s
So third option will be the answer
2(x + 6) is what you’re looking for. Have a good day!
Answer:
3.25 or 3 1/4
Step-by-step explanation:
2 3/4=2.75
2.75+0.5=3.25