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3 years ago

Identify the vertex for the graph of y = −3x2 + 6x − 4. (1, 5) (1, −1) (−1, −13) (−1, −9)

2 answers:

5 0

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-3}x^2\stackrel{\stackrel{b}{\downarrow }}{+6}x\stackrel{\stackrel{c}{\downarrow }}{-4} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{6}{2(-3)}~~,~~-4-\cfrac{6^2}{4(-3)} \right)\implies \left(1~~,~~-4+\cfrac{36}{12} \right) \\\\\\ (1~~,~~-4+3)\implies (1~,-1)$

Nutka1998 [239]3 years ago

3 0

Answer: (1,-1)

Step-by-step explanation:

Took the test. Got i right

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