For the function f(x) = 6x - 8, identify the values of f(o), f(1/2), and f(-2).

Mathematics

2 answers:

igor_vitrenko [27]2 years ago

5 0

Answer:

-8, -5, -20.

Step-by-step explanation:

f(0) = 6(0) - 8 = -8

f(1/2) = 6(1/2) - 8 = -5

f(-2) = 6(-2) - 8 = -20.

Fudgin [204]2 years ago

3 0

$\text{Hello there!}\\\\\text{You're plugging in the values 0, 0.5, and -2 to x}\\\\\text{Plug them into the equation:}\,\,f(x) = 6x - 8\\\\\text{Solve:}\\\\f(x) = 6(0) - 8\\\\\boxed{f(x)=-8}\\\\f(x) = 6(0.5) - 8\\\\f(x) = 3 - 8\\\\\boxed{f(x)=-5}\\\\f(x) = 6(-2) - 8\\\\f(x)=-12-8\\\\\boxed{f(x)=-20}\\\\\text{Those three solutions will be your answer}\\\\\large\boxed{\text{Answer:}\,\,-8;-5;-20}$

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Find the length of a segment with endpoints Y(2, 8) and Z(- 2, 5) .

Andrej [43]

<em>The distance the length of a segment with endpoints Y(2, 8) and Z(-2, 5) is 5 units</em>

<h2>Explanation:</h2>

Endpoints of a Line segments are places where they end or stop. Line segments are named after their endpoints. In this case, those endpoints are Y and Z, so the line segment would be:

$\overline{YZ} \ or \ \overline{ZY}$

To find the length of this segment with endpoints Y(2, 8) and Z(-2, 5), let's use the Distance Formula:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$Let's \ write: \\ \\ Y(x_{1},y_{1}) \rightarrow Y(2, 8) \\ \\ Z(x_{2},y_{2}) \rightarrow (-2, 5) \\ \\ \\ Substituting: \\ \\ d=\sqrt{(-2-2))^2+(5-8)}^2 \\ \\ d=\sqrt{(-4)^2+(-3)^2} \\ \\ d=\sqrt{16+9} \\ \\ d=\sqrt{25} \\ \\ \boxed{d=5}$