We have an triangle:
base=4 in
height=3 in,
This triangle can be dividided into two equal triangles, we need calculate the hypotenuse.
leg₁=4 in/2=2 in
leg₂=3 in
Pythagoras law:
hypotenuse²=leg₁²+leg₂²
hypotenuse²=(2 in)²+(3 in)²
hypotenuse²=4 in²+9 in²
hypotenuse²=13 in²
hypotenuse=√13 in.
Now, we can find the surface area.
Surface area=2 *(rectangle area)+base area + 2(triangle area)
rectangle area=10 in x √13 in=10√13 in²
base area=10 in x 4 in=40 in²
Triangle area=(4 in x 3 in)/2=6 in²
Surface area=2(10√13 in²)+40 in²+2(6 in²)=(20√13+52) in²≈124.11 in²
Answer: 124.11 in²
Answer:
the answer is 140
Step-by-step explanation:
9514 1404 393
Answer:
17 ft, 27 ft, 20 ft
Step-by-step explanation:
Let s represent the length of the shortest side. The the longest side is (2s-7) and the third side is (s+3). The perimeter is the sum of the side lengths:
64 = s +(2s -7) +(s +3)
64 = 4s -4 . . . . . . . . . . . collect terms
16 = s -1 . . . . . . . . . . divide by 4
17 = s . . . . . . . . . add 1
2s -7 = 2·17 -7 = 27 . . . . . the length of the longest side
s +3 = 17 +3 = 20 . . . . . . . the length of the third side
The side lengths are 17 feet, 27 feet, and 20 feet.
If angles are vertical it means opposite angles are the same size. Therefore the measures of the other three angles are 72 degrees, 108 degrees, and 108 degrees. I hope this helps!
