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tatyana61 [14]
3 years ago
11

A researcher reports the following confidence interval for a comparison of the difference between two groups: 95% CI −12.0 [−30.

0 to 6.0].
If there was no difference between groups, then a difference of 0 was expected. 1.

What would the decision have likely been if the researcher tested this hypothesis with hypothesis testing at a .05 level of significance? Explain.

What is the value of the point estimate?
Mathematics
1 answer:
Lapatulllka [165]3 years ago
7 0

Answer:

Decision: Support the null hypothesis.

Sample mean: -12

Step-by-step explanation:

Hello!

When deciding with a Confidence interval you have to keep in mind that the following conditions are met:

  • The hypothesis and the interval are made for the same parameter.
  • The hypothesis should be two-tailed.
  • The interval and the test have to have complementary confidence and signification levels. This means that if the interval is made with 1 - α= 0.95 the hypothesis test should be made with α= 0.05.

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

If the interval contains the cero, it means that there is no difference between the means, so you support the null hypothesis.

If the interval doesn't contain the cero, there is a difference between the two means, so you reject the null hypothesis.

The intervals to estimate the population mean have the following structure:

Estimator ± Margin of error

This means that the sample mean (point estimate of the population mean) is in the middle of the calculated interval. To know it's the value you have to do a simple calculation:

sample mean: \frac{Upper bound + Lower bound}{2}

sample mean: \frac{6 + (-30)}{2}

sample mean: -12

I hope it helps!

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3) Solve these problems that have more than one answer.
MaRussiya [10]

Answer:

225

Step-by-step explanation:

Mary = 3x (3 times Carey)

Carey = x

Barry = x/2 (Because Carey read twice as many as Barry, it means he read half the amount Carey did)

3x + x + x/2 = 405

4x + x/2 = 405

8x/2 + x/2 (treat these as fractions) = 405

9x/2 = 405

9x = 810 (cross multiply)

x = 90

Mary = 3(90)      270

Carey =              90

Barry = 90/2      45

Mary - Barry

270 - 45 = 225

Hope this helps! :)

5 0
2 years ago
Read 2 more answers
PLEASE HELP PRE CAL!!
Len [333]

Answer:

Width = 2x²

Length = 7x² + 3

Step-by-step explanation:

∵ The area of a rectangle is 14x^{4}+6x^{2}

∵ Its width is the greatest common monomial factor of 14x^{4} and 6x²

- Let us find the greatest common factor of 14 , 6 and x^{4} , x²

∵ The factors of 14 are 1, 2, 7, 14

∵ The factors of 6 are 1, 2, 3, 6

∵ The common factors of 14 and 6 are 1, 2

∵ The greatest one is 2

∴ The greatest common factor of 14 and 6 is 2

- The greatest common factor of monomials is the variable with

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∴ The greatest common factor of x^{4} and  x² is x²

∴ The greatest common monomial factor of  14x^{4} and 6x² is 2x²

∴ The width of the rectangle is 2x²

To find the length divide the area by the width

∵ The area = 14x^{4}+6x^{2}

∵ The width = 2x²

∴ The length = ( 14x^{4}+6x^{2}) ÷ (2x²)

∵  14x^{4} ÷ 2x² = 7x²

∵ 6x² ÷ 2x² = 3

∴ ( 14x^{4}+6x^{2}) ÷ (2x²) = 7x² + 3

∴ The length of the rectangle is 7x² + 3

8 0
3 years ago
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Answer:

C.

Step-by-step explanation:

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3 years ago
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Solve this inequality j/4 - 8 < 4
zubka84 [21]
J/4 - 8 < 4
<u>    + 8   + 8  </u>   *add 8 to both sides to cancel -8.
j/4      < 12
<u>*4/1       *4/1   </u>   *multiply 4/1 to both sides to cancel 1/4
j         < 48

j should be less than 48 to make the inequality true.

example: j = 47
j/4       - 8 < 4
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11.75 - 8 < 4
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Any number below 48 will end up with an answer less than 4. if j is 48 and above, the inequality is false because the answer arrived at will be equal to or greater than 4.
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3 years ago
Find the distance between (4,6) and (-2, -2)
Nataly [62]

Answer:

\displaystyle d = 10

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (4, 6)

Point (-2, -2)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute [DF]:                     \displaystyle d = \sqrt{(-2-4)^2+(-2-6)^2}
  2. Subtract:                                \displaystyle d = \sqrt{(-6)^2+(-8)^2}
  3. Exponents:                            \displaystyle d = \sqrt{36+64}
  4. Add:                                       \displaystyle d = \sqrt{100}
  5. Evaluate:                               \displaystyle d = 10
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3 years ago
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