Answer:
225
Step-by-step explanation:
Mary = 3x (3 times Carey)
Carey = x
Barry = x/2 (Because Carey read twice as many as Barry, it means he read half the amount Carey did)
3x + x + x/2 = 405
4x + x/2 = 405
8x/2 + x/2 (treat these as fractions) = 405
9x/2 = 405
9x = 810 (cross multiply)
x = 90
Mary = 3(90) 270
Carey = 90
Barry = 90/2 45
Mary - Barry
270 - 45 = 225
Hope this helps! :)
Answer:
Width = 2x²
Length = 7x² + 3
Step-by-step explanation:
∵ The area of a rectangle is 
∵ Its width is the greatest common monomial factor of
and 6x²
- Let us find the greatest common factor of 14 , 6 and
, x²
∵ The factors of 14 are 1, 2, 7, 14
∵ The factors of 6 are 1, 2, 3, 6
∵ The common factors of 14 and 6 are 1, 2
∵ The greatest one is 2
∴ The greatest common factor of 14 and 6 is 2
- The greatest common factor of monomials is the variable with
the smallest power
∴ The greatest common factor of
and x² is x²
∴ The greatest common monomial factor of
and 6x² is 2x²
∴ The width of the rectangle is 2x²
To find the length divide the area by the width
∵ The area = 
∵ The width = 2x²
∴ The length = (
) ÷ (2x²)
∵
÷ 2x² = 7x²
∵ 6x² ÷ 2x² = 3
∴ (
) ÷ (2x²) = 7x² + 3
∴ The length of the rectangle is 7x² + 3
Answer:
C.
Step-by-step explanation:
J/4 - 8 < 4
<u> + 8 + 8 </u> *add 8 to both sides to cancel -8.
j/4 < 12
<u>*4/1 *4/1 </u> *multiply 4/1 to both sides to cancel 1/4
j < 48
j should be less than 48 to make the inequality true.
example: j = 47
j/4 - 8 < 4
47/4 - 8 < 4
11.75 - 8 < 4
3.75 < 4
Any number below 48 will end up with an answer less than 4. if j is 48 and above, the inequality is false because the answer arrived at will be equal to or greater than 4.
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
Point (4, 6)
Point (-2, -2)
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute [DF]:

- Subtract:

- Exponents:

- Add:

- Evaluate:
