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2 years ago

Multiply. Answers should be in simplest form. 3/7 x10

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

5 0

Answer:

4.28

I think this it. I used a calculator online to help solve this problem. I don't know what the answer is but I used an online calculator to solve the problem. I rounded the answer to the nearest hundreth.

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What are the missing terms 64, -32, 16, -8, ___, ___?

Daniel [21]

Divide by -2 for all of the numbers

64/-32=-2

-32/ 2= -16

-16/2= -8

-8/-2= 4

4/-2= -2

Answer : 4 ,-2

5 0

3 years ago

Read 2 more answers

What is the solution to this equation x/5=15<br> a.x=75<br> b.x=20<br> c.x=3<br> d.x=10

Darina [25.2K]

$\dfrac{x}{5}=15\ \ \ \ |\cdot5\\\\\not5\cdot\dfrac{x}{\not5}=5\cdot15\\\\x=75$

Answer: a. x = 75

8 0

3 years ago

The formula I = PRT where I = Interest, P = principal, R = rate, and T = time is used to calculate the amount of simple interest

andre [41]

Answer:

Step-by-step explanation:

I=PRT

T=I/PR

6 0

2 years ago

Solve 2 1/2 divided by 5 1/3 = 8/x

ipn [44]

$2\frac { 1 }{ 2 } \quad divided\quad by\quad 5\frac { 1 }{ 3 } \\ \\ 2\frac { 1 }{ 2 } =2+\frac { 1 }{ 2 } =\frac { 5 }{ 2 } \\ \\ 5\frac { 1 }{ 3 } =5+\frac { 1 }{ 3 } =\frac { 15+1 }{ 3 } =\frac { 16 }{ 3 } \\ \\ \\ \frac { \frac { 5 }{ 2 } }{ \frac { 16 }{ 3 } }$

We're dividing fractions, so we will flip the one in the denominator upside down and we will multiply it with the numerator.

$\frac { \frac { 5 }{ 2 } }{ \frac { 16 }{ 3 } } \quad =\quad \frac { 5 }{ 2 } \cdot \frac { 3 }{ 16 } =\frac { 5\cdot 3 }{ 2\cdot 16 } =\frac { 15 }{ 32 }$

Let's equal this too 8/x

$\frac { 15 }{ 32 } =\frac { 8 }{ x }$

Cross multiply.

$8\cdot 32=15\cdot x\\ \\ 256=15x$

Divide both sides by 15.

$\frac { 256 }{ 15 } =\frac { 15x }{ 15 } \\ \\ \frac { 256 }{ 15 } =x$

4 0

2 years ago

You are filling up a cylindrical tank with a radius of 5m with water at a rate of 3 cm^3/min. Unbeknownst to you the tank has a

Umnica [9.8K]

Answer:

dh/dt = 3/25π m/min

Step-by-step explanation:

Radius = 5m

Rate (dV/dt) = 3 cm^3 / min

Leaking rate = 1 cm^3 / min

Volume = πr^2h

Volume = π(5)^2h

V= 25πh

Differentiate volume implicitly with respect to time

dV/dt = 3 cm^3/min

3 = 25π(dh/dt)

dh/dt = 3 m^3/min /25πm^2

dh/dt = 3/25πm/min

8 0

2 years ago