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3 years ago

Multiply. Answers should be in simplest form. 3/7 x10

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

5 0

Answer:

4.28

I think this it. I used a calculator online to help solve this problem. I don't know what the answer is but I used an online calculator to solve the problem. I rounded the answer to the nearest hundreth.

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line w passes through point (-6,-7) and has a slope 1/2. what is the equation for the line in point-slope form?

Elena L [17]

Answer:

y + 7 = $\frac{1}{2}$ (x + 6)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

Here m = $\frac{1}{2}$ and (a, b ) = (- 6, - 7 ) , then

y - (- 7) = $\frac{1}{2}$ (x - (- 6) ) , that is

y + 7 = $\frac{1}{2}$ (x + 6)

8 0

2 years ago

Read 2 more answers

The color of any object depends upon which colors are reflected and absorbed. True or False?

SSSSS [86.1K]

Answer:

true

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Brandon earns a rebate each month on his meals and movie tickets. He earns $0.50 for each movie ticket and $2 for each meal. Las

AURORKA [14]

Let ticket be x and meal be y

So $0.50 for each movie ticket = 0.50x

$2 for each meal = 2y

He purchased 22 tickets, so x = 22

0.50 * 22 = $ 11

Now the total value is $25 (with both ticket and meal)

total = t

0.50x + 2y = t

you know x = 22 and t = 25

11 + 2y = 25

Part A)

2y = 25 -11

y = 14/2

y = 7

Number of meal is 7

Part B)

(don't know about part B)

0.50x + 2y = 25

0.50(22) + 2(7) = 25

11 + 14 = 25

25 = 25

7 0

3 years ago

If Ben invests $4500 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that

pogonyaev

$Step \; 1: \; Assing \; variable \; for \; the \; unknown \; that \; we \; need \; to \; find.\\Let \; x \; be \; additional \; money \; invested$

$Step \; 2: \; Use \; the \; appropriate \; formula \; of \; simple \; interest \; set \; up \; an \; equation\\Interest \; earned \; each \; year = \; Amount \; invested \times annual \; rate \; of \; interest\\\\Amount \; invested \; in \; 4 \% \; rate \; of \; interest=\$4500\\Amount \; invested \; in \; 5\frac{1}{2}\% \; rate \; of \; interest= \$x\\Amount \; invested \; totally \; in \; 4\frac{1}{2}\% \; rate \; of \; interest = \$(4500+x)$

$Interest \; earned \; in \; 4\% \; interest \; rate\\ = \; 4500(4\%)=180\\Interest \; earned \; in \; 5\frac{1}{2}\% \; interest \; rate\\ = x(5\frac{1}{2}\%)=0.055x\\Interest \; earned \; totally \; in \; 4\frac{1}{2}\% \; interest \; rate = (4500+x)(4\frac{1}{2}\%)\\=0.045(4500+x)$

$\\\\So, \; the \; equation \; would \; be:\\180+0.055x=0.045(4500+x)$

$Step \; 1: \; Distribute \; 0.045 \; in \; the \; right \; side\\180+0.055x=202.5+0.045x\\\\Step \; 2: \; Subtract \; 0.045x \; and \; 180 \; on \; both \; sides \; to \; get \; x \; alone\\0.055x-0.045x=202.5-180\\\\Step \; 3: \; Combine \; Like \; Terms\\0.01x=22.5\\\\Step \; 4: Divide \; 0.01 \; on \; both \; sides\\\frac{0.01x}{0.01}=\frac{22.5}{0.01}\\\\Step \; 5: \; Simplifying \; fraction \; on \; both \; sides\\x=2250$

$\underline{Conclusion:}\\Ben \; should \; invest \; additional \; money \; of \; \$2250$

5 0

3 years ago

Experimental probability

natulia [17]

What are you asking here exactly

7 0

3 years ago