Which number is IRRATIONAL? A) 16 B) 25 C) 48 D) 100

What is the genral form of (x-6)2+(y-4)2=56

dusya [7]

X+y=38 that’s your answer

5 0

2 years ago

Allison is offered an annual salary of $24,500. What would be her biweekly gross pay? (Round to the nearest cent.) A. $2,041.67

bixtya [17]

Answer:

Option (B) is correct.

Allison biweekly gross pay is $942.31

Step-by-step explanation:

Given annual salary offered to Allison = $24,500.

We have to calculate Allison biweekly pay that is pay Allison got for 2 weeks

To calculate biweekly we first find Allison weekly pay then multiply it by 2.

We know there are 52 weeks in a year.

So, weekly salary offered to Allison $=\frac{24500}{52}=471.15$ (approx)

Biweekly salary will be = 2 × weekly salary

= 2 × 471.15

= 942.307(approx)

Thus, Allison biweekly gross pay is $942.31

6 0

3 years ago

Read 2 more answers

The pie chart to the right shows how adults rate their financial shape. Suppose 4 people are chosen at random from a group of 14

Salsk061 [2.6K]

Question Completion

PIE CHART NUMBERS:

Excellent 9%
Good 41%
Fair 36%
Poor 13%
Other 1%

Answer:

0.000063

Step-by-step explanation:

Number of Respondents, n=1400

Probability that they would rate their financial shape as excellent = 0.09

Number of Those who would rate their financial shape as excellent

=0.09 X 1400

=126

Therefore:

The probability that 4 people chosen at random would rate their financial shape as excellent

$=\dfrac{^{126}C_4 \times ^{1400-126}C_0}{^{1400}C_4} \\=\dfrac{^{126}C_4 \times ^{1274}C_0}{^{1400}C_4}\\=0.000063 $(correct to 6 decimal places)$

6 0

3 years ago

Graph the function y= 3/2x^3. Plot five points on the graph of the function: one point with x = 0, two points with negative x-va

Nat2105 [25]

Answer:

(a square +7a+12) ÷(a+3)

5 0

2 years ago

An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba

madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

X = a person is overweight

Y = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688$

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

$P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312$

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0

2 years ago