Answer: Subnet mask
Explanation:
Subnet mask is the type of parameter that should be match in order to form the adjacency for running the OSPFv2. The subnet mask is mainly used to identifying the address of network in the system.
The OSPF enable the router that must form an adjacency with the neighbors before sharing any type of data.
It mainly determine the neighbors links in the OSPF. The OSPFv2 router send the special type of message which is known as hello packet in the network.
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Answer:
#include<iostream>
using namespace std;
void OutputMinutesAsHours(double origMinutes) { //Same as question
double hours=origMinutes/60; //solution is here
cout<<hours;
}
//Below is same as mentioned in question
int main() {
OutputMinutesAsHours(210.0);
cout << endl;
return 0;
}
OUTPUT :
3.5
Explanation:
In the above code, only two lines are added. To convert minutes into hours we have to divide them 60, so we take minutes as input and define a new variable of double type which stores minutes converted to hours and then that variable is printed to console. For 210, it gives 3.5, similarly for 3600 it gives 60 and so on.
The answer for this question is true
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>