Question

Please help me with my math! Thank You! :)

Answer 1

Answer:

cosΘ = $\frac{4}{5}$

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1 ⇒ cosx = ± $\sqrt{1-sin^2x}$

Given

sinΘ = $\frac{3}{5}$, then

cosΘ = ± $\sqrt{1-(3/5)^2}$ = ± $\sqrt{1-\frac{9}{25} }$ = ± $\sqrt{\frac{16}{25} }$ = ± $\frac{4}{5}$

Since Θ is in first quadrant then cosΘ > 0

cosΘ = $\frac{4}{5}$

Answer 2

Then Cos would be 4/5