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deff fn [24]
3 years ago
12

If sine of x equals square root of 2 over 2, what is cos(x) and tan(x)? Explain your steps in complete sentences.

Mathematics
1 answer:
vredina [299]3 years ago
5 0
Sinx=\frac{opposite}{hypotenuse} =\frac{ \sqrt{2} }{2}
     opposite=\sqrt{2}
     hypotenuse=2

Adjacent^{2}+(\sqrt{2 })^{2 }= 2 ^{2}
<span>Adjacent^{2}+2=4
</span><span>Adjacent^{2}=2 
</span>Adjacent=\sqrt{2}

cosx=\frac{ajc}{hyp}= \frac{ \sqrt{2} }{2}
Tanx=\frac{opp}{adj} =  \frac{ \sqrt{2} }{ \sqrt{2} }
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This is not the only answer possible. There are infinitely many possible answers.

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Explanation:

We start with the given equation x = -2

Multiply both sides by some number. I'll pick 10

So if we multiply both sides by 10, we get

10*x = 10*(-2)

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Now let's add something to both sides. Let's say we add 7 to both sides

10x+7 = -20+7

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Finally, let's divide both sides by 2

(10x+7)/2 = -13/2

You could keep going to add, subtract, multiply, or divide both sides by some number. This process can continue indefinitely. I'll stop here since we have three operations done.

-------------------

If we were to solve (10x+7)/2 = -13/2, we would get to x = -2

To solve (10x+7)/2 = -13/2, we follow the steps done in the previous section in reverse.

So we'll undo the "divide both sides by 2" operation by multiplying both sides by 2.

Then we'll undo the "add 7 to both sides" operation to subtract 7 from both sides

Lastly, we'll undo the "multiply both sides by 10" by dividing both sides by 10.

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Expand this out:

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