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Bingel [31]
3 years ago
7

I need help. I do not know if I am wrong or right.

Mathematics
2 answers:
kotykmax [81]3 years ago
7 0

Answer:

I think you are correct

Step-by-step explanation:

Virty [35]3 years ago
7 0
You’re right just saying :)
You might be interested in
Solve for x using the<br> distributive property.<br> 9(5 - x) = 81<br> x = [?]
Ilya [14]

Answer:

\boxed {x = -4}

Step-by-step explanation:

Solve for the value of x:

9(5 - x) = 81

-Use <u>Distributive Property</u>:

9(5 - x) = 81

45 - 9x = 81

-Subtract 45 to both sides:

45 - 45 - 9x = 81 - 45

-9x = 36

-Divide both sides by:

\frac{-9x}{-9} = \frac{36}{-9}

\boxed {x = -4}

So, the value of x is -4.

8 0
3 years ago
What is the place of the 9 in the number 5,948,003
tino4ka555 [31]
The 9 is in the one hundred thousand's place
4 0
3 years ago
Read 2 more answers
Unscramble the place value.write three forms of number 9 hundreds+4ten thousands+8 ones+7 tens
liubo4ka [24]
40,978 would be the answer hope it helped!
3 0
3 years ago
Read 2 more answers
Evaluate the expression
Neporo4naja [7]

Simplify the expression.

Exact form:

\frac{476}{25}

Decimal form:

19.04

Mixed Number Form:

19\frac{1}{25}

8 0
3 years ago
When Rafael emptied his pockets, e found he had a total of $3.50 in quarters and nickels. If he had 8 more quarters that nickels
jasenka [17]
You can use systems of equations for this one.

We are going to use 'q' as the number of quarters Rafael had,
and 'n' as the number of nickels Rafael had.


You can write the first equation like this:
3.50=0.05n+0.25q
This says that however many 5 cent nickels he had, and however many
25 cent quarters he had, all added up to value $3.50.
Our second equation is this:
q=n+8
This says that Rafael had 8 more nickels that he had quarters.

We can now use substitution to solve our system.

We can rewrite our first equation from:
3.50=0.05n+0.25q
to:
3.50=0.05n+0.25(n+8)

From here, simply solve using PEMDAS.

3.50=0.05n+0.25(n+8)     --Distribute 0.25 to the n and the 8
3.50=0.05n+0.25n+2     --Subtract 2 from both sides
1.50=0.05n+0.25n     --Combine like terms
1.50=0.30n     --Divide both sides by 0.30
5=n     --This is how many NICKELS Rafael has.

We now know how many nickels he has, but the question is asking us
how many quarters he has.

Simply substitute our now-known value of n into either of our previous
equations (3.50=0.05n+0.25q or q=n+8) and solve.

We now know that Rafael had 13 quarters.

To check, just substitute our known values for our variables and solve.
If both sides of our equations are equal, then you know that you have
yourself a correct answer.

Happy math-ing :)
5 0
3 years ago
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