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vovangra [49]
3 years ago
6

To make extra money Jeremy is building bookcases for some teachers at his school. If Jeremy builds 1 bookcase in 45 minutes, whi

ch is a reasonable estimate of the amount of time it will take him to build 35 bookcases?
Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
6 0
It will take him about 1,575 minutes to build 35 bookcases.
babymother [125]3 years ago
4 0
1575 would be about correct!

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Whats 25/7 as a mixed number?
Ann [662]
\frac{25}{7}=\frac{21+4}{7}=\frac{21}{7}+\frac{4}{7}=3+\frac{4}{7}=3\frac{4}{7}
6 0
3 years ago
Find the sum. Enter your answer in the box below as a fraction, using the slash mark ( / ) for the fraction bar.
Rom4ik [11]

Answer:

5/7

Step-by-step explanation:

2/7 + 3/7

Denominator are equal so adding numerator,

(2+3)/7 = 5/7

5 0
3 years ago
2(4x - 1) + 3(3 - 2x) = 0
LUCKY_DIMON [66]
2(4x-1) + 3(3-2x)=0
distribute
8x-2+9-6x=0
add like terms
2x+7=0
subtract 7 from both sides
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divide both sides by 2
x=-7/2
3 0
3 years ago
How do you add a fraction with different denomirers
e-lub [12.9K]
Hey there!
When we're adding with different denominators, our goal is to keep the equivalent fraction, but create like denominators.
Let's think of an easier situation. If we have the number 5 and we want an equivalent number, we multiply by one. It's no different with fractions. We want to multiply by some version of one, like 2/2 or 4/4
For example, if we have:
2/8 + 4/6

Our LCM is 24. Therefore, we multiply 2/8 by 3/3:
2/8(3/3) = 6/24

And 4/6 by 4/4:
4/6(4/4) = 16/24

As you can see, we multiplied by versions of 1, so they're still the same fraction.

We have:
16/24 + 6/24 = 22/24 = 11/12

Hope this helps!
5 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=ex/7; [0,7]
Anastaziya [24]

Answer:

f_{avg}=e-1

Step-by-step explanation:

We are given that a function

f(x)=e^{\frac{x}{7}}

We have to find the average value of function on the given interval [0,7]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{7-0}\int_{0}^{7}e^{\frac{x}{7}} dx

f_{avg}=\frac{1}{7}[e^{\frac{x}{7}}\times 7)]^{7}_{0}

By using the formula

\int e^{ax}=\frac{e^{ax}}{a}

f_{avg}=(e-e^0)=e-1

Because e^0=1

f_{avg}=e-1

Hence, the average value of function on interval [0,7]

f_{avg}=e-1

8 0
3 years ago
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