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vazorg [7]
3 years ago
13

A and B are complementary angles. If m_A = (6x + 29) and m

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
6 0

Answer:

m∠A=77°

Step-by-step explanation:

Complementary angles are a pair of angles whose measures have a sum of 90°. Since m∠A = 6x+29 and m∠B = x+5, we can write the following equation to solve for x:

6x+29+x+5=90

Solving for x, we get:

6x+29+x+5=90

7x+34=90 (Simplify LHS)

7x+34-34=90-34 (Subtract 34 from both sides of the equation to isolate x)

7x=56 (Simplify)

\frac{7x}{7}=\frac{56}{7} (Divide both sides of the equation by 7 to get rid of x's coefficient)

x=8

Therefore, m∠A=6x+29=6(8)+29=48+29=77°. Hope this helps!

almond37 [142]3 years ago
6 0

Answer:

The measurement of angle A is: 77°

Step-by-step explanation:

First of all, let us define complementary angles

The angles whose sum is 90° are called complementary angles.

Given angles are:

m∠A = 6x+29

m∠B = x+5

With respect to the definition, the sum of both angles will be 90°

Writing this mathematically we get

A+B = 90\\6x+29+x+5 = 90\\7x+34=90\\7x = 90-34\\7x = 56\\\frac{7x}{7} = \frac{56}{7}\\x = 8

Putting the value of x in the expression for angle A

A = 6x+ 29 = 6(8)+29 =48+29\\A = 77

Hence,

The measurement of angle A is: 77°

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The product of two odd numbers is an odd number.

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Step-by-step explanation:

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3 years ago
A cube has a volume of 343 cm3. What is the length of each side of the cube?
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Please show me how to solve for Xsquared - 21.75X = -15.75. I have the solution but do not know how to solve it.
Andreas93 [3]
x^2-21.75x=-15.75 \\
x^2-21.75x+15.75=0

Use the quadratic formula:
x^2-21.75x+15.75=0 \\ \\
a=1 \\ b=-21.75 \\ c=15.75 \\ b^2-4ac=(-21.75)^2-4 \times 1 \times 15.75=473.0625-63=410.0625 \\ \\
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-21.75) \pm \sqrt{410.0625}}{2 \times 1}=\frac{21.75 \pm 20.25}{2} \\
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\boxed{x=\frac{3}{4} \hbox{ or } x=21}
3 0
3 years ago
If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers​
seraphim [82]

Answer:

  • a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}

<h2>Simplify it in steps:</h2>

<h3>Step 1</h3>

Bring both fractions into common denominator:

\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}

<h3>Step 2</h3>

Simplify:

\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =

\dfrac{4\sqrt{14} }{7-4} =

\dfrac{4}{3}  \sqrt{14} }

<h3>Step 3</h3>

Compare the result with given expression to get:

  • a = 4/3 and b = 0

4 0
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