3 years ago

If 3x^2-2x+7=0 then (x-1/3)^2=

1 answer:

5 0

3x^2−2x+7=0
3x^2−2x+1/3+7−1/3=0
3(x^2−2x/3+1/9)+7−1/3=0
3(x−1/3)^2+(21−1)/3=0
3(x−1/3)^2=−20/3
(x−1/3)^2=−20/9

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