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lilavasa [31]
3 years ago
5

If 3x^2-2x+7=0 then (x-1/3)^2=

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0
<span>3x^2−2x+7=0
</span>3x^2−2x+1/3+7−1/3=<span>0
</span><span>3<span>(x^2−2x/3+1/9)</span>+7−1/3=0
</span><span>3<span><span>(x−1/3)^</span>2</span>+(21−1)/3=0
</span><span>3<span><span>(<span>x−1/3</span>)^</span>2</span>=−<span>20/3
</span></span><span><span>(<span>x−<span>1/3</span></span>)^</span>2</span>=−<span>20/9</span>
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AveGali [126]

Answer:

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Step-by-step explanation:

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<u />

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The number of different ways that this could play out is

              (7 x 6 x 5 x 4 x 3 x 2 x 1)  =  <em>5,040</em>


6 0
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