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lilavasa [31]
3 years ago
5

If 3x^2-2x+7=0 then (x-1/3)^2=

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0
<span>3x^2−2x+7=0
</span>3x^2−2x+1/3+7−1/3=<span>0
</span><span>3<span>(x^2−2x/3+1/9)</span>+7−1/3=0
</span><span>3<span><span>(x−1/3)^</span>2</span>+(21−1)/3=0
</span><span>3<span><span>(<span>x−1/3</span>)^</span>2</span>=−<span>20/3
</span></span><span><span>(<span>x−<span>1/3</span></span>)^</span>2</span>=−<span>20/9</span>
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Factor completely. 2x^4+4x^3-30x^2
kramer

Answer:

Step-by-step explanation:

2x⁴ + 4x³ - 30x² = 2x²*(x² + 2x - 15)

x² + 2x - 15

Sum = 2

Product = -15

Factors = 5 ; (-3)

x² + 2x - 15 = x² + 5x - 3x - 3 *5

                  = x(x + 5) - 3(x + 5)

                  = (x + 5)(x - 3)

2x⁴ + 4x³ - 30x² = (2x²) (x + 5)(x - 3)

7 0
4 years ago
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

So, we have to impose

x-7\geq 0 \iff x \geq 7

Squaring both sides, we have

(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0
3 years ago
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Oxana [17]

Answer:

13 protons

14 neutrons

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Step-by-step explanation:

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7 0
3 years ago
I need to show the work. Please help
Juliette [100K]

Answer:

x=23

Step-by-step explanation:

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8x-77=3x+38

Then you get like terms on the same sides by subtracting 3x from both sides and getting:

5x-77=38

Then you add 77 to both sides and get:

5x=115

Then you divide both sides by 5 and get x=23

3 0
3 years ago
How many 5/16's are in 1 &amp; 7/8? *
Vilka [71]

Answer:

oh so for one get them to look alike.. sooo keep 5/16 and change 1 7/8 to

1  14/16 and then  change it to 30/16 then simply compare 5 can go into 30 6 times soooooo    it can go into 1 & 7/8  6 times

Step-by-step explanation:

5 0
3 years ago
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