Plz Help me Brainliest to whoever answers first

Mathematics

1 answer:

Anna11 [10]2 years ago

5 0

16 I believe please mark BRAINLIEST

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In a field, dry fodder for the cattle is heaped in a

ipn [44]

Answer:

volume of fodder=1/3pie R^2h= $\frac{1}{3} *\frac{22}{7} * (3.6)^2 *2.1=28.51m^3$

l^2=r^2+h^2

l^2=(2.1)^2+(3.6)^2

l^2=4.441+12.96=17.37

l= $\sqrt{17.37}$ =4.17m

minimum area of polythene to cover fodder=pieRl= $\frac{22}{7} *3.6*4.17=47.18m^2$

the volume of fodder is $28.51m^3$ and minimum area of polythene to cover fodder in the rainy seasonv47.18m^3

3 0

2 years ago

Write 0.05 as a fraction. A) 1 12 B) 1 15 Eliminate C) 1 18 D) 1 9

zheka24 [161]

$x=0.0\overline{5}\\\\x=0.0555...\qquad\text{multiply both sides by 10}\\\\10x=0.555...\qquad\text{multiply both sides by 10}\\\\100x=5.555...\\\\\text{Make the difference:}\\\\100x-10x=5.555...-0.555...\\\\90x=5\qquad\text{divide both sides by 90}\\\\x=\dfrac{5}{90}\\\\x=\dfrac{5:5}{90:5}\\\\x=\dfrac{1}{18}\\\\Answer:\ \boxed{0.0\overline{5}=\dfrac{1}{18}}\to\boxed{C)}$