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3 years ago

12

a rectangle is a four sided flat shaped where every interior angles is a right angle. Therefore, opposite sides aRE PARALLEL and

consecutive sides are perpendicular.

1 answer:

Schach [20]3 years ago

5 0

This is true. There is no question connected which is why there are no answers!

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Bob bought 5 packs of toilet paper for $42.50. Which equation can be used to determine the price, p, in dollars, of 1 pack of to

Contact [7]

Answer:

42.50/5 = p is the equation; $8.50 per pack

Step-by-step explanation:

DIVIDE 42.50 between the 5 packs of toilet paper.

THIS GETS YOU $8.50 per pack.

THE EQUATION used was 42.50/5 = p.

4 0

3 years ago

The points A, B, and C lie on a line so that AB = 12 cm and BC = 13.5 cm. Find the length of segment AC. Give all possible answe

natita [175]

Answer:

25.5 and 1.5

Step-by-step explanation:

AC = 12 cm

BC = 13.5 cm

12 + 13.5 = 25.5 cm

13.5 - 12 = 1.5 cm

4 0

3 years ago

How can you add 3over 10 and 2over5

otez555 [7]

Answer:

7/10

Step-by-step explanation:

3/10+2/5

You have to make like denominators

So you multiply 2/5 by 2 since 1/ is the common denominator.

Then you add them

Hope this helped

6 0

3 years ago

Read 2 more answers

The complement of set M is ______.

Firlakuza [10]

Answer:

M' is {-5, -4, -3, -2, -1, 0, 1, 3, 5, 6}

Step-by-step explanation:

6 0

3 years ago

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,

professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so $\mu = 7*0.6 = 4.2$

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150$

$P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630$

$P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323$

So

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103$

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0

3 years ago