Answer:
9,-7 hope this helps :))))))))
Answer:
DE = 6 cm
Step-by-step explanation:
Let DE = x cm.
Since DE is parallel to AB therefore by the alternate interior angles theorem, m∠BAD = m∠ADE and m∠ABE = m∠DEB ............(1)
As AD is an angle bisector of ∠A, therefore m∠EAD = m∠DAB ; Since BE is an angle bisector of ∠B ⇒ m∠ABE = m∠EBD.
Therefore, from (1) We get , m∠EAD = m∠ADE and m∠EBD = m∠BED.
So, the triangles ADE and EDB are then isosceles with AE = ED and ED = DB.
So AE = DE = DB = x, and since the perimeter of ABDE is 30 cm, then
12 + x + x + x = 30
⇒ 12 + 3x = 30
⇒ x = 6
Hence, the length of DE is 6 cm.
X+(x+1)+(x+2)+(x+3)=156
4x+6=156
4x=150
x=37.5 (not an integer)
If x=37 you get 37+38+39+40=154 and if x=38 you get 38+39+40+41=158[/tex]
(t-2)(t+1)(t+1)
t^2+t-2t-2(t+1)
t^2-t-2(t+1)
t^3-t^2-2t+t^2-t-2
t^3+-3t-2
Answer:
4
Step-by-step explanation: