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igomit [66]
3 years ago
7

Page 2

Mathematics
1 answer:
stepan [7]3 years ago
7 0
You wont because 72 +21+15+36+69+81+9+27+42+63=435 and 435 is greater than 100
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diamong [38]

Answer:

the sequence is continuing by multiplying -4

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Depenendent Event
DaniilM [7]

Answer:

.2

Step-by-step explanation:

first you add all the pencils up which is 12 next take the probably of taking out one of each pencil .4 for green .2 for black and .6 for yellow next you divide the probably for pulling 1 green bye 2 since your pulling out 2

8 0
3 years ago
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Find the side length of the equilateral triangle whose area is the square root of 3 cm2
Alla [95]

Here, Given

Area of Equilateral triangle = 3cm2

therefore, we know;

Area of Equilateral triangle =( \sqrt{3}÷4)×a^{2}

so,

3 =( \sqrt{3}÷4)×a^{2}

3÷( \sqrt{3}÷4) = a^{2}

2.63 cm = a .

The area of ​​an equilateral triangle is the area covered by an equilateral triangle on a two-dimensional plane. An equilateral triangle is a triangle with all sides equal and all angles at 60 degrees. The area of ​​the shape is the number of unit squares that fit inside.

Here, "unit" refers to 1, and a unit square is a square with one side. Alternatively, the area of ​​an equilateral triangle is the total amount of space it surrounds in a two-dimensional plane.

Learn more about Area of  triangle  here: brainly.com/question/17335144

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6 0
2 years ago
A shoe store displayed 75 pairs of shoes on 12 shelves. How many pairs of shoes could the store display on eight shelves.
yanalaym [24]
50 pairs of shoes since 75/12 is 6.25 and then multiply 6.25x8
8 0
3 years ago
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A basketball gymnasium is 25 meters high, 80 meters wide and 200 meters long. We want to connect two strings, one from each of t
Rudiy27

Answer:

a) the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be 216.85 m

c) the angle that is formed by the strings is  1.23 rad

Step-by-step explanation:

assuming that we stand on one of the corners on the floor , so our coordinates are (0,0,0)  , then the coordinates of the center of the gymnasium   are found through

x center = (25 + 0)/2 = 12.5 m

y center = (80+ 0)/2 = 40 m

z center = (200+ 0)/2 = 100 m

then the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be the modulus of the vector that points from our position to the diagonally opposite corners

|S| = √(25²+80²+200²) = 216.85 m

c) the angle can be found through the dot product of the vectors that represent the strings S₁ and S₂

S₁ =(25,80,10)

S₂ =(-25,80,100)

then

S₁*S₂ = 25*(-25) +80*80 + 100*100 = 15775

but also

S₁*S₂ = |S₁||S₂| cos θ = |S|² * cos θ

S₁*S₂ =  |S|² * cos θ

cos θ= S₁*S₂/|S|²

θ= cos ⁻¹ ( S₁*S₂/|S|² ) = cos ⁻¹ [15775/(25²+80²+200²)] = 1.23 rad

7 0
3 years ago
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