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Dmitriy789 [7]
3 years ago
6

You start driving north for 35 miles turn right and drive east for another 12 miles at the end of driving what is your straight

line distance from your starting point

Mathematics
2 answers:
Lynna [10]3 years ago
5 0

Answer: The distance = 37 miles

Step-by-step explanation: The question can be tackled by using pythagorean theorem.

The hypothenus of the figure is the straight line distance from the starting point.

Please find the attached file for the solution

I am Lyosha [343]3 years ago
3 0

Answer: The straight line distance from my starting position is 37miles

Step-by-step explanation:

 Now, if I start driving north for thirty five miles, turned right and drive east for 12 miles, at the end of my journey, I can calculate my straight line distance from my starting point.

     In this situation or scenario, we have a right angle triangle if I drove due north, turned right and drove due east. All we need do to calculate the straight line distance from my starting point is to input the Pythagoras formula and substitute accordingly. With this, we can always obtain the straight line distance from my starting position in the right angle triangle formed as a result of my journey.

  The path I took while driving due north will be the opposite. The path I took while driving due east is the adjacent and the straight line distance from my starting point will be the hypotenuse.

  Stating the Pythagoras formula:-

   Hyp^{2}= Opp^{2} + adj^{2}

 Now the opposite in this case is the 35 miles I covered driving north and the adjacent here is the 12 miles covered while driving east. The hypotenuse is the unknown variable. Let us denote it by "x".

  Therefore, x^{2} = 35^{2} + 12^{2}

     x^{2}= 1225 + 144

        x^{2}   = 1369

        x  = \sqrt{1369

        x = 37 miles.

  Therefore, the straight line distance from my starting point is 37 miles.

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3 years ago
A force of 192 lb is required to hold a spring stretched 3 ft beyond its natural length. How much work W is done in stretching i
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Answer:

The work done in stretching the spring is 8 lb.ft

Step-by-step explanation:

Given;

Applied force, F = 192 lb

extension of the spring, x = 3 ft

Determine the spring constant from the applied force and extension;

k = \frac{F}{x} \\\\k = \frac{192 \ lb}{3 \ ft} \\\\k = 64 \ lb/ft

When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;

x = 6 inches = 0.5 ft

W = \frac{1}{2} kx^2\\\\W =  \frac{1}{2} (64 \ lb/ft)(0.5 \ ft)^2\\\\W = 8 \ lb.ft

Therefore, the work done in stretching the spring is 8 lb.ft

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2 years ago
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A function assigns the values. The range of the function will be between (-∞,10].

<h3>What is a Function?</h3>

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The given function f(x)=10-x² is a parabolic function that is negative, therefore, will open downwards. Now, the range of the function can be found as,

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