Answer:
your do it on your own
Step-by-step explanation:
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
y=-16x^2+129x+119
y=−16x
2
+129x+119
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Hello!
To find the quadrant of where the angle 7π/6 radians is located, we will need to convert from radians to degrees. To do that, we will need to multiply it by 180/π.
7π/6 × 180/π = 1260/6 = 210 degrees
Since 210° is between 180° and 270°, then 7π/6 radians is located in the third quadrant shown by: Quadrant III, then 180° < θ < 270°.
Therefore, 7π/6 radians is located in quadrant III.
Answer:
Y=1.25x+3.50
Step-by-step explanation:
The problem is linear so it uses y=ax+b form. In this we can set the left group as x and the right group as y. Then use
(y2-y1) / (x2-x1) to find the slope. once the slope is found (1.25) we can find the y intercept by using one of our coordinates with our equation y-ax=b
12.25-1.25*7=b
b=3.5
now we put them all together to make
Y=1.25x+3.50