Answer:
Is their a picture so we can see where to put it
<h3>Hey there! </h3><h3>The second "
![x](https://tex.z-dn.net/?f=x)
" is has invisible
![1](https://tex.z-dn.net/?f=1)
</h3><h3>Here, this is what I meant:
![x^ 1](https://tex.z-dn.net/?f=x%5E%201)
</h3><h3>So, now your equation looks like this:
![-2)](https://tex.z-dn.net/?f=-2%29)
</h3><h3>Add the exponents:
![= 5](https://tex.z-dn.net/?f=%3D%205)
</h3><h3>Therefore your answer should be:
![x^5 - 2](https://tex.z-dn.net/?f=x%5E5%20-%202)
</h3><h3>(Note: there's many ways to solve these types of equations, I just gave you the basic method) </h3><h3 /><h3>Good luck on your assignment and enjoy your day! </h3><h3>~
![LoveYourselfFirst:)](https://tex.z-dn.net/?f=LoveYourselfFirst%3A%29)
</h3>
Answer:
The probability is 0.28157
Step-by-step explanation:
The number of answers are 40 answers ( 10 questions and 4 answer each)
The number of correct answers is only 10
So the probability that he answers 2 exactly out of 10 means he correctly selected 2 answers
The probability will be;
10 C 2/ 40 C 10
This mean out of the total 10 correct, he selects 2 and out of the total 40 , he selects 10
The probability of selecting a correct answer is;
1/4 while the probability of selecting a wrong one is 3/4
So probability of selecting 2 correct out of a total 10 will be
10 C 2 (1/4)^2 (3/4)^8
= 0.28157
Answer:
C. )
Step-by-step explanation:
Answer:
Option A 90,68
![m\angle 1=90^o](https://tex.z-dn.net/?f=m%5Cangle%201%3D90%5Eo)
![m\angle 2=68^o](https://tex.z-dn.net/?f=m%5Cangle%202%3D68%5Eo)
Step-by-step explanation:
see the attached figure to better understand the problem
The figure shows a kite
we know that
A kite properties include
1) two pairs of consecutive, congruent sides
2) congruent non-vertex angles
3) perpendicular diagonals
Find the measure of angle 1
we have that
----> by the diagonals are perpendicular
Find the measure of angle 2
we know that
triangle AEB is congruent with triangle CEB
so
![m\angle EAB=m\angle ECB=m\angle 2](https://tex.z-dn.net/?f=m%5Cangle%20EAB%3Dm%5Cangle%20ECB%3Dm%5Cangle%202)
In the right triangle EAB
----> by complementary angles in a right triangle
so
![m\angle EAB=90^o-22^o=68^o](https://tex.z-dn.net/?f=m%5Cangle%20EAB%3D90%5Eo-22%5Eo%3D68%5Eo)
therefore
![m\angle 2=68^o](https://tex.z-dn.net/?f=m%5Cangle%202%3D68%5Eo)