The answer is 65, hope this helps
356,000 would be the answer I believe
Answer:
0.2377 or about a 23.77% chance
Step-by-step explanation:
P(123<X<130) = normalcdf(123,130,130,11) = 0.2377303466 ≈ 0.2377
Therefore, the probability that the next game Victoria bowls, her score will be between 123 and 130 is 0.2377 or about a 23.77% chance
Answer:
B (2,8)
Step-by-step explanation:
Q1=3 Q2[median]=12 Q3=14 and the IQR is 11