What is the answer help

Mathematics

1 answer:

ruslelena [56]2 years ago

4 0

Answer: With that assumption, we have a square, whose area is given by the formula Asquare=a2, and two semicircles. The distance D is simply the square's diagonal. The area of each semicircle is given by the formula Asemicircle=π*r2/2. then you will get your answer!

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If m = 5 and n = -2, evaluate 3m - 4n and n2 - m and find the product of the two expressions.

ddd [48]

Hence the correct answer is C) -23

Further explanation:

We have to put the values of m and n into both expression first separately and then multiply the answers.

Given expressions are:

$Exp\ 1:3m-4n\\Exp\ 2: n^2-m$

The values are:

$m=5\\n=-2$

Putting the values in expression 1:

$3m-4n\\=3(5)-4(-2)\\=15+8\\=23$

Putting the values of m and n in second expression

$n^2-m\\=(-2)^2-5\\=4-5\\=-1$

Multiplying both expressions:

$(3m-4n)(n^2-m)=23* (-1)=-23$

Hence the correct answer is C) -23

Keywords: Polynomials, Putting values in expressions

Learn more about polynomials at:

#LearnwithBrainly

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2 years ago

The hanger diagram models the equation 2(n + 7) = 24. What could be the

baherus [9]

Step-by-step explanation:

first of all you times every number with two 2(n-7) then collect like terms then divide

4 0

2 years ago

Solve the separable differential equation dtdx=x2+164 and find the particular solution satisfying the initial condition x(0)=9

maria [59]

$\dfrac{dt}{dx} = x^2 + \frac{1}{64} \Rightarrow\ dt = \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ \\ \displaystyle \int 1 dt = \int \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ t = \dfrac{x^3}{3} + \frac{x}{64} + C$

C = 9 because all the x terms go away.

$t = \dfrac{x^3}{3} + \dfrac{x}{64} + 9$