Answer: Option D
Step-by-step explanation:
Note that the projectile height as a function of time is given by the quadratic equation
To find the maximum height of the projectile we must find the maximum value of the quadratic function.
By definition the maximum value of a quadratic equation of the form
is located on the vertex of the parabola:
Where
In this case the equation is:
Then
So:
Answer:
∡TQS = 10x -3
∡TQS = ∡RQS - ∡RQT
= 22x - 11 - (12x - 8)
= 10x -3