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3 years ago

I will give brainiest to whoever answers correctly !!

Mathematics

1 answer:

Bad White [126]3 years ago

7 0

Answer:

Mortgage cost: $213,000, cost per year: $10,650

Step-by-step explanation:

245000-45000 = 200,000 (the mortgage).

The total cost of the mortgage (t) is: 200000(6.5%)+200000.

t = 213,000

cost per year: 213000/20 = 10,650

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Find Lowest common factor of following questions . 56, 42, 28

Montano1993 [528]

Answer:

$\boxed{\textsf{ The LCM of 56 , 42 , 28 is \textbf{ 168}.}}$

Step-by-step explanation:

We need to find out the LCM of 56 , 42 , 28 . So Lowest Common Multiple known as LCM is the lowest multiple which is divisible by all the numbers whose LCM is taken out . It can we done by two methods. Both of which are discussed in the attachment .

For complete solution kindly refer to the attachment .

Related Information :- 

• HCF :-

It stands for Highest Common Factor . It is the highest numbers which divides out completely the numbers without leaving remainder of the numbers whose HCF is we are finding out .

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3 years ago

HOW DO I DO THISSS ITS LINEAR WORD PROMBLEMS WITH GRAPHS

777dan777 [17]

It took the plane 1700 seconds for the plane to land. If you look at the x-axis, you can see that the x-intercept crosses through the point (0, 1700).

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4 years ago

What is the answer please help me

Licemer1 [7]

Answer:

Step-by-step explanation:

1.58 x n = z

another way of showing:

z = 1.58n

5 0

3 years ago

There are 5 chocolate bars. Each bar is split into 8 pieces.

Ganezh [65]

The total of how many pieces you have

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3 years ago

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A researcher wants to determine whether the number of minutes adults spend online per day is related to gender. A random sample

suter [353]

Answer:

The expected frequency for the cell E2,2 is = 33

Step-by-step explanation:

The given data is

Gender | 0-30| 30-60| 60-90| 90+ Totals

Male | 23 | 35 | 76 | 46 180

Female | 31 | 42 | 46 | 16 135

Totals 54 77 122 62 315

The expected frequency for the cell E2,2 is :

Expected for the (30-60 box for females) = Total of (30-6)/ (total )* females

= ( 77/315)135= 33

Here p= 77/315 and n= 135

therefor X= pn = 33

χ²= (33-42)²/33= 2.455 ( for the single value of E2,2=33)

Expected for the (30-60 box for males) = Total of (30-6)/ (total )* males

= ( 77/315)180= 44

χ²= (44-42)²/44= 0.09

The critical region is χ² (0.05) 3 ≥ χ²= 11.34

Let the null and alternate hypothesis be

H0:the number of minutes spent online per day is not related to gender

against

Ha: the number of minutes spent online per day is related to gender

The single value of χ² for E2,2 = 2.45 is less than the critical value of 11.34.

6 0

3 years ago