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ElenaW [278]
3 years ago
13

Solve the system of equations 9x + 2y = 11 and 9x + y = 1 by combining the equations

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
4 0
The answer to the question

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If 32 horses consume 112 kg of grass in a certain period, how much grass will be
Aloiza [94]

Answer:

38.5 kg of grass

Step-by-step explanation:

We can solve this problem by using a proportion. (Kg of grass over horses)

Let x = the amount of grass 11 horses will eat in the same period of time.

112/32 = x/11      Cross multiply

1232 = 32x        Divide both sides by 32

x = 38.5

I hope this helped and please mark me as brainliest!

4 0
2 years ago
...........................
cupoosta [38]

Answer:

3/5 or 0.6

Step-by-step explanation:

Here, given the value of tan theta , we want to find the value of sine theta

Mathematically;

tan theta = 0pposite/adjacent

Sine theta = opposite/hypotenuse

Firstly we need the length of the hypotenuse

This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.

Let’s call the hypotenuse h

h^2 = 3^2 + 4^2

h^2 = 9 + 16

h^2 = 25

h = √(25)

h = 5

Now from the tan theta, we know that the opposite is 3

Thus, the value of the sine theta = 3/5 or simply 0.6

5 0
3 years ago
Write at least three expressions that are equivalent to 3(2x - 5)
myrzilka [38]

Answer:

6x - 15

6x - (5 · 3)

(3 · 2x) - 15

6 0
3 years ago
Read 2 more answers
Solve for x. 7^8=7^8×7^x
denis-greek [22]

Answer:

x = 0

Step-by-step explanation:

Apply the exponent rule.

7^8=7^{x+8} \\

If a^{f(x)} = a^{g(x)}  then f(x) = g(x)

8 = x + 8

x = 0

3 0
3 years ago
Using the feasible region below, determine which x and y values will maximize the profit, P, in the equation P = 40x + 55y * 1 p
Kay [80]

Answer:

B (300, 400)

Step-by-step explanation:

The profit maximization will be when the sum of the products will be greater. The maximum profit will be when x is 300 and y is 400. If we put in the equation :

P = 40x + 55 y

A - When x =  0 , y = 500

P = [40 * 0] + [55 * 500]

P = 27500

B -

When x =  300 , y = 400

P = [40 * 300] + [55 * 400]

P = 34000

C -

When x =  380 , y = 200

P = [40 * 380] + [55 * 200]

P = 26200

D -

When x =  400 , y = 0

P = [40 * 400] + [55 * 400]

P = 16000

7 0
3 years ago
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