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Natali [406]
2 years ago
8

Please help! & don’t answer with “don’t know the answer”

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
8 0

Answer:

c

Step-by-step explanation:

x+x=90

2x=90 ,x=45 ,∆BAD=45

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The number of hours per week that the television is turned on is determined for each family in a sample. The mean of the data is
katovenus [111]

Answer:

200\ families

Step-by-step explanation:

Already, we are given 12% of our sample size as 24.

To find the sample size, we equate to find 100%.

Let sample size be denoted by t

If\  12\%=24\\100\%=t\\t=\frac{100\%\times24}{12\%}\\=200

Hence, the sample has 200 families.

7 0
3 years ago
Find the area of the trapezoid
DiKsa [7]

Answer:

20 is the answer

Step-by-step explanation:

I did the math.hope it helps :)

3 0
3 years ago
Brian invests £7900 into his bank account.
DENIUS [597]

Step-by-step explanation:

1. use the equation

current amount X interest to the power of years

commpound interest is 2.3%

The starting value is £7900

So: £7900*1.023^5=£8851.26

Therefore, the answer is £8851.26 after 5 years of interest added

Hope this helps!!!

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7 0
3 years ago
What is 3a squared add 7 a
vfiekz [6]
The answer is:  " 9a² + 7a " .
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Note:    (3a)² + 7a = (3a)*(3a) + 7a = 9a² + 7a .
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3 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
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